已知:x+y=12,xy=9,则x²y+2xy²分之x²+3xy+2y²=
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已知:x+y=12,xy=9,则x²y+2xy²分之x²+3xy+2y²=
![已知:x+y=12,xy=9,则x²y+2xy²分之x²+3xy+2y²=](/uploads/image/z/16237400-32-0.jpg?t=%E5%B7%B2%E7%9F%A5%3Ax%2By%3D12%2Cxy%3D9%2C%E5%88%99x%26%23178%3By%2B2xy%26%23178%3B%E5%88%86%E4%B9%8Bx%26%23178%3B%2B3xy%2B2y%26%23178%3B%3D)
x²y+2xy²分之x²+3xy+2y²=
=(x+2y)(x+y)/xy(x+2y)
=(x+y)/xy
=12/9
=4/3
=(x+2y)(x+y)/xy(x+2y)
=(x+y)/xy
=12/9
=4/3
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