如图,在五边形ABCDE中,已知AB=AE,BC=ED,对角线AC=AD
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如图,在五边形ABCDE中,已知AB=AE,BC=ED,对角线AC=AD
求证:(1)△ABC≌△AED;
(2)∠B=∠E
![](http://img.wesiedu.com/upload/0/3c/03c42631dbf922d9d0651c14386690e8.jpg)
求证:(1)△ABC≌△AED;
(2)∠B=∠E
![](http://img.wesiedu.com/upload/0/3c/03c42631dbf922d9d0651c14386690e8.jpg)
![如图,在五边形ABCDE中,已知AB=AE,BC=ED,对角线AC=AD](/uploads/image/z/16139366-62-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%BA%94%E8%BE%B9%E5%BD%A2ABCDE%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5AB%3DAE%2CBC%3DED%2C%E5%AF%B9%E8%A7%92%E7%BA%BFAC%3DAD)
1、由AB=AE,BC=ED,AC=AD(sss)全等得证
2、△ABC≌△AED,由三角形判定定理,所以)∠B=∠E
2、△ABC≌△AED,由三角形判定定理,所以)∠B=∠E
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