解方程组 {2x+3y/4+2x-3y/3=7,2x+3y/3-2x-3y/2=32
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解方程组 {2x+3y/4+2x-3y/3=7,2x+3y/3-2x-3y/2=32
1.在方程x-3y=5,当x=-1时,y=
2.已知{4x-3y-2z=0,x-3y-z=0,那么x:y=
1.在方程x-3y=5,当x=-1时,y=
2.已知{4x-3y-2z=0,x-3y-z=0,那么x:y=
![解方程组 {2x+3y/4+2x-3y/3=7,2x+3y/3-2x-3y/2=32](/uploads/image/z/16129547-35-7.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%84+%7B2x%2B3y%2F4%2B2x-3y%2F3%3D7%2C2x%2B3y%2F3-2x-3y%2F2%3D32)
1.x-3y=5 得到 3y =x-5 故y=(x-5)/3
当x= -1时,y=(-1-5)/3= - 6/3= -2
2.要求x:y的值,就要把z消掉,所以:
x-3y-z=0两边同时乘以2,即:2x-6y-2z=0 与4x-3y-2z=0两式联立相减消去z:
( 2x-6y-2z)-(4x-3y-2z)=0 得到:
-2x-3y=0 所以:2x=-3y
故:x :y= -3 :2
当x= -1时,y=(-1-5)/3= - 6/3= -2
2.要求x:y的值,就要把z消掉,所以:
x-3y-z=0两边同时乘以2,即:2x-6y-2z=0 与4x-3y-2z=0两式联立相减消去z:
( 2x-6y-2z)-(4x-3y-2z)=0 得到:
-2x-3y=0 所以:2x=-3y
故:x :y= -3 :2
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