已知x+2y=1,x-2y=7,求x²-4y²的值
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已知x+2y=1,x-2y=7,求x²-4y²的值
![已知x+2y=1,x-2y=7,求x²-4y²的值](/uploads/image/z/16127731-19-1.jpg?t=%E5%B7%B2%E7%9F%A5x%2B2y%3D1%2Cx-2y%3D7%2C%E6%B1%82x%26%23178%3B-4y%26%23178%3B%E7%9A%84%E5%80%BC)
x²-4y²
=(x+2y)(x-2y)
=1*7
=7
=(x+2y)(x-2y)
=1*7
=7
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