观察下列等式:① cos2α=2 cos2 α-1; ② cos 4α=8 cos4 α-8 cos2 α+1; ③ c
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观察下列等式:① cos2α=2 cos2 α-1; ② cos 4α=8 cos4 α-8 cos2 α+1; ③ cos 6α=32 cos6 α-
![观察下列等式:① cos2α=2 cos2 α-1; ② cos 4α=8 cos4 α-8 cos2 α+1; ③ c](/uploads/image/z/16073524-28-4.jpg?t=%E8%A7%82%E5%AF%9F%E4%B8%8B%E5%88%97%E7%AD%89%E5%BC%8F%EF%BC%9A%E2%91%A0+cos2%CE%B1%3D2+cos2+%CE%B1%EF%BC%8D1%EF%BC%9B+%E2%91%A1+cos+4%CE%B1%3D8+cos4+%CE%B1%EF%BC%8D8+cos2+%CE%B1%2B1%EF%BC%9B+%E2%91%A2+c)
题目应该是(2110福建文科题)
观察下列等式:
① cos2α=2 (cos α)^2-1;
② cos 4α=8 (cos )^4-8 (cosα)^2+1;
③ cos 6α=32 (cosα)^6-48 (cosα)^4+18( cosα)^2-1;
④ cos 8α= 128 (cosα)^8-256(cosα)^6+160 (cosα)^4-32 (cosα)^2+1;
⑤ cos 10α=m(cosα)^10-1280 (cosα)^8+1120(cosα)^6+n(cosα)^4+p(cosα)^2-1;
可以推测,m-n+p=
答案:962.
观察下列等式:
① cos2α=2 (cos α)^2-1;
② cos 4α=8 (cos )^4-8 (cosα)^2+1;
③ cos 6α=32 (cosα)^6-48 (cosα)^4+18( cosα)^2-1;
④ cos 8α= 128 (cosα)^8-256(cosα)^6+160 (cosα)^4-32 (cosα)^2+1;
⑤ cos 10α=m(cosα)^10-1280 (cosα)^8+1120(cosα)^6+n(cosα)^4+p(cosα)^2-1;
可以推测,m-n+p=
答案:962.
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