(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
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(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?
![(4m+2)(2m+4n)如何化成4(2m+n)(m+2n)?](/uploads/image/z/16051854-30-4.jpg?t=%EF%BC%884m%2B2%29%282m%2B4n%29%E5%A6%82%E4%BD%95%E5%8C%96%E6%88%904%EF%BC%882m%2Bn%29%28m%2B2n%29%3F)
(4m+2)(2m+4)=[2*(2m+1)]*[2*(m+2)]=4(2m+n)(m+2n)
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
因式分解4m^2(m-n)+4n(n-m)
[(m-n)^2*(m-n)^3]^2/(m-n)^4
(m-n)2(n-m)3(n-m)4化简
(3m-4n)(4n+3m)-(2m-n)(2m+n)
[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]
计算(m+4n)(m-n)-6(m+2n)(m-3n)
(m+4n)(m-n)-6(m+2n)(m-3n),
证明(m+n)²/2+(m+n)/4≥(m√n)+(n√m)
(m+4n)(m-n)-6(m+2n)(m-3n)
先化简,在求值(m+n)(m-n)(-m^2-n^2)-(-2m+n)(-2m-n)(4m^2+n^2) 其中m=1,n
2(m+n)2-(m+n)+4(m+n)-(m+n)2+3(m+n)2 化简求值