解方程x^2+(200+0.5x)^2=4X^2
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解方程x^2+(200+0.5x)^2=4X^2
![解方程x^2+(200+0.5x)^2=4X^2](/uploads/image/z/16036995-3-5.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8Bx%5E2%2B%28200%2B0.5x%29%5E2%3D4X%5E2)
x^2+(200+0.5x)^2=4X^2
(200+0.5x)^2-3x^2=0
(200+0.5x+√3x)(200+0.5x-√3x)=0
200+(0.5+√3)x=0 200+(0.5-√3)x=0
x1=-200/(0.5+√3) =800 (0.5-√3)/11
x2=-200/(0.5-√3) = 800 (0.5+√3)/11
(200+0.5x)^2-3x^2=0
(200+0.5x+√3x)(200+0.5x-√3x)=0
200+(0.5+√3)x=0 200+(0.5-√3)x=0
x1=-200/(0.5+√3) =800 (0.5-√3)/11
x2=-200/(0.5-√3) = 800 (0.5+√3)/11
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