若△ABC的三边a,b,c满足a²+b²+c²+338=10a+24b+26c,则S△AB
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若△ABC的三边a,b,c满足a²+b²+c²+338=10a+24b+26c,则S△ABC=
![若△ABC的三边a,b,c满足a²+b²+c²+338=10a+24b+26c,则S△AB](/uploads/image/z/15915051-27-1.jpg?t=%E8%8B%A5%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9a%2Cb%2Cc%E6%BB%A1%E8%B6%B3a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%2B338%3D10a%2B24b%2B26c%2C%E5%88%99S%E2%96%B3AB)
a=5,b=12,c=13,△ABC是直角三角形.
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