题如下、 已知2x+y=0,求x2+xy分之x-2y乘以(x2-y2)除以
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题如下、 已知2x+y=0,求x2+xy分之x-2y乘以(x2-y2)除以
x分之x2-4xy+4y2的值.
求(X2+XY)分之(X-2Y)乘以(X2-Y2)除以(X)分之(X2-4XY+4Y2)的值
x分之x2-4xy+4y2的值.
求(X2+XY)分之(X-2Y)乘以(X2-Y2)除以(X)分之(X2-4XY+4Y2)的值
{[(x-2y)/(x^2+xy)]/(x^2-y^2)}*/[(x^2-4xy+4y^2)/x]
=x(x-2y)/[(x^2+xy)(x^2-y^2))(x^2-4xy+4y^2)]
=x(x-2y)/[x(x+y)(x-y)(x+y)(x-2y)^2]
=1/[(x-y)(x+2y)(x+y)^2]
=x(x-2y)/[(x^2+xy)(x^2-y^2))(x^2-4xy+4y^2)]
=x(x-2y)/[x(x+y)(x-y)(x+y)(x-2y)^2]
=1/[(x-y)(x+2y)(x+y)^2]
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