Please help me to solve this question with working please. T
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Please help me to solve this question with working please. TQ
Candle A and candle B are of the same length. Candle A, which is broader, can burn for 5 hours while Candle B, the thinner candle, can burn for 4 hours. If both candles are lighted at the same time, how long does it take for candle A to be twice as long left as candle B?
Candle A and candle B are of the same length. Candle A, which is broader, can burn for 5 hours while Candle B, the thinner candle, can burn for 4 hours. If both candles are lighted at the same time, how long does it take for candle A to be twice as long left as candle B?
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Let t be the time elapsed.(设t为经过的时间)
1-(1/5)t=2(1-(1/4)t)
t=10/3
Therefore,after 3 hours and 20 minutes,candle A is twice as long left as candle B.
(答:经过3小时20分钟,蜡烛A剩余长度为蜡烛B的两倍.)
1-(1/5)t=2(1-(1/4)t)
t=10/3
Therefore,after 3 hours and 20 minutes,candle A is twice as long left as candle B.
(答:经过3小时20分钟,蜡烛A剩余长度为蜡烛B的两倍.)
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