整式乘法与因式分解由这个(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0 怎么能到这个x-y=1/2(1)
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整式乘法与因式分解
由这个(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0
怎么能到这个x-y=1/2(1)
由这个(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0
怎么能到这个x-y=1/2(1)
![整式乘法与因式分解由这个(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0 怎么能到这个x-y=1/2(1)](/uploads/image/z/15837107-59-7.jpg?t=%E6%95%B4%E5%BC%8F%E4%B9%98%E6%B3%95%E4%B8%8E%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E7%94%B1%E8%BF%99%E4%B8%AA%28x-y%29%5E2-2%28x-y%29%2A%281%2F2%29%2B%281%2F2%29%5E2%3D0+%E6%80%8E%E4%B9%88%E8%83%BD%E5%88%B0%E8%BF%99%E4%B8%AAx-y%3D1%2F2%281%29)
(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0
(x-y-1/2)^2=0
x-y-1/2=0
x-y=1/2
(x-y-1/2)^2=0
x-y-1/2=0
x-y=1/2
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