若m-n=2,a-n=3,则式子[(2m-2n-4)²;+(a-n-3)²]÷[(m+n+a)
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若m-n=2,a-n=3,则式子[(2m-2n-4)²;+(a-n-3)²]÷[(m+n+a)²+1]的值为
![若m-n=2,a-n=3,则式子[(2m-2n-4)²;+(a-n-3)²]÷[(m+n+a)](/uploads/image/z/15831172-28-2.jpg?t=%E8%8B%A5m%EF%BC%8Dn%3D2%2Ca%EF%BC%8Dn%3D3%2C%E5%88%99%E5%BC%8F%E5%AD%90%5B%EF%BC%882m%EF%BC%8D2n%EF%BC%8D4%EF%BC%89%26%23178%3B%3B%2B%EF%BC%88a%EF%BC%8Dn%EF%BC%8D3%EF%BC%89%26%23178%3B%5D%C3%B7%5B%EF%BC%88m%2Bn%2Ba%EF%BC%89%26%231)
=[(4-4)(4-4)+(3-3)(3-3)]/ [(m+n+a)²+1]
=0/ [(m+n+a)²+1]
=0
=0/ [(m+n+a)²+1]
=0
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