x+y=3 y+z=4 x+z=5怎么做
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x+y=3 y+z=4 x+z=5怎么做
X+Y=3 X+Z=5 Y+Z=4三式相加,得
2x+2y+2z=12,得x+y+z=6分别减原来三个式子,得
x=2,y=1,z=3
再问: 2x-y=2 3x-3y+2z=7 x + 2 y - 2 z = 1
2x+2y+2z=12,得x+y+z=6分别减原来三个式子,得
x=2,y=1,z=3
再问: 2x-y=2 3x-3y+2z=7 x + 2 y - 2 z = 1
(x+y-z)(x-y+z)=
x/2=y/3=z/5 x+3y-z/x-3y+z
怎么做3元一次方程2x+3y+z=6x-y+2z=1x+2y-z=5
x=3,y=4,z=5,求以下表达式的值,怎么算 (x && y)==(x || z) (x>y)+(y!=z) ||
已知3X=4X,5Y=6Z求X+Y:Y+Z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?
3x+7y+z=5 ,4x+10y+z=6 ,x+y+z=
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?