[x-x/(x+1)]*[(x+1)/(x^2+3x+2)]÷[(x^2-2x)/(x^2-4)]

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/07/28 03:56:50

[x-x/(x+1)]*[(x+1)/(x^2+3x+2)]÷[(x^2-2x)/(x^2-4)]
一楼的纯粹是瞎扯

[x-x/(x+1)]*[(x+1)/(x^2+3x+2)]÷[(x^2-2x)/(x^2-4)]
=x²/(x+1)×(x+1)/(x+1)(x+2)×(x²-4)/(x²-2x²)
=x²/(x+1)×(x+1)/(x+1)(x+2)×(x-2)(x+2)/x(x-2)
=x/(x+1)

x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4) |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) 1+x+x^2+x^3+.+x^99+x^100 x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 |x^2-3x-4|>x+1 {2X+1}+{X} x^2-|x|+1 ｜x-1｜+｜x-2｜