(1/2)*|5k-4|*|(4/k)-5|=5;第二道题:(1/2)*|2k+2|*|-(2+2k)/k|=1的解是多
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(1/2)*|5k-4|*|(4/k)-5|=5;第二道题:(1/2)*|2k+2|*|-(2+2k)/k|=1的解是多少?
![(1/2)*|5k-4|*|(4/k)-5|=5;第二道题:(1/2)*|2k+2|*|-(2+2k)/k|=1的解是多](/uploads/image/z/15661647-63-7.jpg?t=%281%2F2%29%2A%7C5k-4%7C%2A%7C%284%2Fk%29-5%7C%3D5%EF%BC%9B%E7%AC%AC%E4%BA%8C%E9%81%93%E9%A2%98%EF%BC%9A%281%2F2%29%2A%7C2k%2B2%7C%2A%7C-%282%2B2k%29%2Fk%7C%3D1%E7%9A%84%E8%A7%A3%E6%98%AF%E5%A4%9A)
第一道题:原式→|(5k-4)(4/k-5)|=10→|(5k-4)^2/k|=10→(5k-4)^2/|k|=10→分别讨论k>0和k0和k
代数式K/K-5-2与K+1/K的值互为相反数,则K=?
1^k+2^k+3^k+4^k+5^k.+n^k数列和公式的推导
当k等于?时,3k(2k-5)+2k(1-3k)=52
求证:lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1
[k*(2-4k)/(1+2k)]+2k+1
请问1^k+2^k+3^k+.+n^k=?
3×k×k-2k-1=-1.k等于
K-1+K+2+K/3+K*3=2001
证明(K/K+1)+{1/(K+1)(K+2)}=(K+1)/K+2
解方程:{(2-3k)/(k+1)-(3k+2)/(1-k)}的平方+{(5k)/(k+1)-(5k)/(1-k)}的平
化简:k-1/k²-4k+4÷1-k/k²-4的结果是( ) A、2-k/k+2 B、k+2/k-2
((k²)²-4k²+2k+5)/k²+1分解因式