解方程2(x²+ 1/x²)-3(x+ 1/x)-1=0
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/09 16:55:38
解方程2(x²+ 1/x²)-3(x+ 1/x)-1=0
![解方程2(x²+ 1/x²)-3(x+ 1/x)-1=0](/uploads/image/z/15513844-4-4.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B2%28x%26%23178%3B%2B+1%2Fx%26%23178%3B%29-3%28x%2B+1%2Fx%29-1%3D0)
令x+1/x=t
t^2=x^2+1/x^2+2
x^2+1/x^2=t^2-2
原方程变为:
2(t^2-2)-3t-1=0
2t^2-3t-5=0
(2t-5)(t+1)=0
t1=5/2,t2=-1(舍去)
x+1/x=5/2
x^2+1=5x/2
2x^2-5x+2=0
(2x-1)(x-2)=0
x1=1/2 x2=2
t^2=x^2+1/x^2+2
x^2+1/x^2=t^2-2
原方程变为:
2(t^2-2)-3t-1=0
2t^2-3t-5=0
(2t-5)(t+1)=0
t1=5/2,t2=-1(舍去)
x+1/x=5/2
x^2+1=5x/2
2x^2-5x+2=0
(2x-1)(x-2)=0
x1=1/2 x2=2
解方程(x²-3x)/(x²-1)+(2x-1)/(x-1)=0
解方程(x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0
解方程:x²+3x-1=x-2
解方程:x(6-x)-2x(x+1)-(x^3-3x^4)/x²=4
解方程(x²-x+4)x-(x-1)(x²+2)=x+7
解方程:x(x+2)+(2x+1)(2x-1)=5(x²+3)
(x+1)(2x-3)-(x-1)(x+2)=x²+7,解方程,
解方程:2(x-3)(x+1)=x²+(x-1)(x+2)
解方程:(x+1)(x-1)=x(2x+3)-(x-2)²
解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
解方程 x(x+1)-x-9=0 x²-2x=224 x(x-2)=2(2-x) x²-(2(√2)