设y=sin(3x^[2]+[5]x+1),求dy/dx.
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设y=sin(3x^[2]+[5]x+1),求dy/dx.
![设y=sin(3x^[2]+[5]x+1),求dy/dx.](/uploads/image/z/15496047-63-7.jpg?t=%E8%AE%BEy%3Dsin%283x%5E%5B2%5D%2B%5B5%5Dx%2B1%29%2C%E6%B1%82dy%2Fdx.)
dy/dx=(6x+5)*cos(3x^2+5x+1)
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