几道求导数的题麻烦帮帮忙,
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/01 14:51:49
几道求导数的题麻烦帮帮忙,
今天赶作业发现求导的题不会怎么做,明天就要交来不及学了,能写多少算多少,感激不尽!
![](http://img.wesiedu.com/upload/a/c7/ac7223e035bdacf409e31abc26cdba0e.jpg)
![几道求导数的题麻烦帮帮忙,](/uploads/image/z/15474101-5-1.jpg?t=%E5%87%A0%E9%81%93%E6%B1%82%E5%AF%BC%E6%95%B0%E7%9A%84%E9%A2%98%E9%BA%BB%E7%83%A6%E5%B8%AE%E5%B8%AE%E5%BF%99%2C)
a.y=e^(x/cosx) dy/dx=e^(x/cosx) (cosx+xsinx)/cos²x=secx(1+xtanx) e^(x/cosx)
b.y=ln 5x/(1+e^2x) dy/dx=[(1+e^2x)/x - 2e^2x ln5x]/(1+e^2x)²
c.cosx-siny y'=cosxcosy - sinxsiny y' ,y' siny (1-sinx)=cosx(1-cosy) ,
y'=cosx(1-cosy)/[(1-sinx)siny]
d.dy/dx=(lnx)^x (lnx+1)
e.y'=x^(-2/3)/3 e^x^4 (x^2+1)^5 +x^(1/3)(4x^3 e^x^4)(x^2+1)^5 + x^(1/3)e^x^4[5(x^2+1)2x]
f.2yy'=6x^2-4x^3 y'=2x^2(3-2x)/(2y)
b.y=ln 5x/(1+e^2x) dy/dx=[(1+e^2x)/x - 2e^2x ln5x]/(1+e^2x)²
c.cosx-siny y'=cosxcosy - sinxsiny y' ,y' siny (1-sinx)=cosx(1-cosy) ,
y'=cosx(1-cosy)/[(1-sinx)siny]
d.dy/dx=(lnx)^x (lnx+1)
e.y'=x^(-2/3)/3 e^x^4 (x^2+1)^5 +x^(1/3)(4x^3 e^x^4)(x^2+1)^5 + x^(1/3)e^x^4[5(x^2+1)2x]
f.2yy'=6x^2-4x^3 y'=2x^2(3-2x)/(2y)