初二数学计算题 已知2x-y=10,求((x^2+y^2)-(x-y)^2+2y(x-y))/4y
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初二数学计算题 已知2x-y=10,求((x^2+y^2)-(x-y)^2+2y(x-y))/4y
![初二数学计算题 已知2x-y=10,求((x^2+y^2)-(x-y)^2+2y(x-y))/4y](/uploads/image/z/15456163-67-3.jpg?t=%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E8%AE%A1%E7%AE%97%E9%A2%98+%E5%B7%B2%E7%9F%A52x-y%3D10%2C%E6%B1%82%EF%BC%88%28x%5E2%2By%5E2%29-%28x-y%29%5E2%2B2y%28x-y%29%29%2F4y)
((x^2+y^2)-(x-y)^2+2y(x-y))/4y
=(x^2+y^2-(x^2-2xy+y^2)+(2xy-2y^2))/4y
=(x^2+y^2-x^2+2xy-y^2+2xy-2y^2)/4y
=(4xy-2y^2)/4y
=2y(2x-y)/4y
=(2x-y)/2
当2x-y=10时
原式=10/2=5
=(x^2+y^2-(x^2-2xy+y^2)+(2xy-2y^2))/4y
=(x^2+y^2-x^2+2xy-y^2+2xy-2y^2)/4y
=(4xy-2y^2)/4y
=2y(2x-y)/4y
=(2x-y)/2
当2x-y=10时
原式=10/2=5
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