(2x+y)²-(x+2y)²怎样算求过程
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(2x+y)²-(x+2y)²怎样算求过程
![(2x+y)²-(x+2y)²怎样算求过程](/uploads/image/z/15435457-25-7.jpg?t=%EF%BC%882x%2By%29%26%23178%3B-%28x%2B2y%29%26%23178%3B%E6%80%8E%E6%A0%B7%E7%AE%97%E6%B1%82%E8%BF%87%E7%A8%8B)
原式=[(2x+y)+(x+2y)][(2x+y)-(x+2y)]
=(3x+3y)(x-y)
=3(x+y)(x-y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
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