分解因式:x3+2x2y+2xy2+y3=______.
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分解因式:x3+2x2y+2xy2+y3=______.
![分解因式:x3+2x2y+2xy2+y3=______.](/uploads/image/z/15380901-45-1.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9Ax3%2B2x2y%2B2xy2%2By3%3D______%EF%BC%8E)
x3+2x2y+2xy2+y3=(x3+y3)+(2x2y+2xy2)
=(x+y)(x2-xy+y2)+2xy(x+y)
=(x+y)(x2+xy+y2)
故答案为:(x+y)(x2+xy+y2)
=(x+y)(x2-xy+y2)+2xy(x+y)
=(x+y)(x2+xy+y2)
故答案为:(x+y)(x2+xy+y2)
已知A=x3-2y3+3x2y+xy2-3xy+4,B=y3-x3-4x2y-3xy-3xy2+3,C=y3+x2y+2
把多项式x3-4x2y+4xy2分解因式,结果为______.
已知A=x3+3x2y-5xy2+6y3-1,B=y3+2xy2+x2y-2x3+2,C=x3-4x2y+3xy2-7y
因式分解:x3-y3-x2y+xy2
若代数式x3+y3+3x2y+axy2含有因式x-y,则a=______,在实数范围内将这个代数式分解因式,得x3+y3
有这样一道题:“计算(2x3-3x2y-2xy2)-(x3-2xy2+y3)+(-x3+3x2y-y3)的值,其中x=1
分解因式:x2y+2xy+y=______.
分解因式.(1)9a-ab2(2)3x3-6x2y+3xy2(3)a2(2a-3)+b2(3-2a)
把多项式3xy2-3x2y-y3+x3按字母x降幂排列为______.
把多项式3x2y-4xy2+x3-5y3按y的降幂排列是______.
小明在解答题目:“已知x=3,y=-1,求代数式(x3+3x2y-5xy2+6x3+1)-(2x3-y3-2xy2-x2
已知(x+2)2+|y-1|=0,求x3(是三次方,打不出来)+3x2y+3xy2+y3(同上) 要有过程.