lim(x→0)[6(x/sinx)ln(1+2x)^(1/2x)]谢谢了,
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lim(x→0)[6(x/sinx)ln(1+2x)^(1/2x)]谢谢了,
lim(x→0)[6(x/sinx)ln(1+2x)^(1/2x)]求详细解答过程
lim(x→0)[6(x/sinx)ln(1+2x)^(1/2x)]求详细解答过程
![lim(x→0)[6(x/sinx)ln(1+2x)^(1/2x)]谢谢了,](/uploads/image/z/15379251-51-1.jpg?t=lim%28x%E2%86%920%29%5B6%28x%2Fsinx%29ln%281%2B2x%29%5E%281%2F2x%29%5D%E8%B0%A2%E8%B0%A2%E4%BA%86%2C)
lim(x→0)(x/sinx)=1 lim(x→0)ln(1+2x)^(1/2x)=1/2 lim(x→0)(1+2x)/x=1/2 lim(x→0)2x/x=1所以原式等于6(x→0)(x/sinx)lim(x→0)(x/sinx)=6*1*1=6
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