已知x-3y=0,求(x^2-2xy+y^2分之2x+y)×(x-y)的值?
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已知x-3y=0,求(x^2-2xy+y^2分之2x+y)×(x-y)的值?
![已知x-3y=0,求(x^2-2xy+y^2分之2x+y)×(x-y)的值?](/uploads/image/z/1229674-58-4.jpg?t=%E5%B7%B2%E7%9F%A5x-3y%3D0%2C%E6%B1%82%28x%5E2-2xy%2By%5E2%E5%88%86%E4%B9%8B2x%2By%29%C3%97%28x-y%29%E7%9A%84%E5%80%BC%3F)
x-3y=0
x=3y
(x^2-2xy+y^2分之2x+y)×(x-y)
=(2x+y)/(x-y)^2*(x-y)
=(2x+y)/(x-y)
=(6y+y)/(3y-y)
=7y/2y
=7/2
x=3y
(x^2-2xy+y^2分之2x+y)×(x-y)
=(2x+y)/(x-y)^2*(x-y)
=(2x+y)/(x-y)
=(6y+y)/(3y-y)
=7y/2y
=7/2
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