y=sin(x a) 根号3cos(x-a)的图像关于y轴对称,则a的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/19 17:11:52
![y=sin(x a) 根号3cos(x-a)的图像关于y轴对称,则a的值](/uploads/image/f/910851-51-1.jpg?t=y%3Dsin%28x+a%29+%E6%A0%B9%E5%8F%B73cos%28x-a%29%E7%9A%84%E5%9B%BE%E5%83%8F%E5%85%B3%E4%BA%8Ey%E8%BD%B4%E5%AF%B9%E7%A7%B0%2C%E5%88%99a%E7%9A%84%E5%80%BC)
y=根号3cos²x+sinxcosx-根号3/2=√3(1/2cos2x+1/2)+1/2sin2x-√3/2=√3/2cos2x+√3/2+1/2sin2x-√3/2=√3/2cos2x
1,x=π/4,y=π/3或者x=3π/4,y=2π/32,(2√2-1)/3
y=sinα+√3cosα=2(1/sinα+√3/2cosα)=2(sinαcos(π/3)+cosαsin(π/3))=2sin(α+π/3)
因为是偶函数,所以,sin(y+x)+根号3cos(x-y)=sin(y-x)+根号3cos(-x-y)所以,可以展开:sinycosx+cosysinx+根号3cosxcosy+根号3sinxsin
y=1-4(sinx)^2-2倍根号3sin(2x)=1-2(1-cos2x)-2倍根号3sin(2x)=4sin(π/6-2x)-1当x∈[0,π/2],π/6-2x属于[-5π/6,π/6]所以最
y=3sin派x+根号cos派x=3-3(根号cos派x)^2+根号cos派x=-[根号3cos派x-1/(2根号3)]^2+3+1/12=-[根号3cos派x-1/(2根号3)]^2+37/12函数
这题只要判断sin根号2-sin根号3,cos根号2-cos根号3的正负;这里要知道π/2≈1.57,√2≈1.41,√3≈1.73;于是√2<π/2<√3<ππ/2-√3<π/2-√2,所以sin根
y=(√3/2)sin(x+π/2)+cos(π/6-x)=(√3/2)cosx+cos(π/6)cosx+sin(π/6)sinx=(√3/2)cosx+(√3/2)cosx+(1/2)sinx=√
(1)原式=2[(1/2)sin(x/2)+(根号3/2)cos(x/2)]=2sin[(x/2)+pi/3]所以当[(x/2)+pi/3]=2kpi+pi/2时,y最大值为2解得x=4kpi+pi/
2sinα-cosα=根号3sinαcosα=(2-根号3)sinαcos^2α=(2-根号3)^2sin^2α=(7-4根号3)(1-cos^2α)(1+7-4根号3)cos^2α=7-4根号34(
y=2(2cos²x-1)+2倍根号三sin2xy=2cos2x+2倍根号三sin2xy=4(1/2倍cos2x+根号三/2倍sin2x)y=4sin(π/6+2x)三角函数解析式有了想要什
sin(cosa)>=0所以2kπ
y=-(cos²x-sin²x)-√3sinxcosx=-cos2x-(√3/2)sin2x=-sin(2x+π/6)或者y=-(cos²x-sin²x)-√3
是求两个函数(1)y=√(sinx)(2)y=√(cosx)的定义域吧还是求(3)y=√sin(cosx)定义域(1)要使y=√(sinx)有意义,须令sinx≥0所以2kπ≤x≤π+2kπ,k∈z即
1.f(x)=sinx+√3cosx=√(1+3)sin(x+π/3)=2sin(x+π/3)最大值是ymax=2,最小值是ymin=-22.y=cos²x-sin²x=cos2x
y=cos²x+2√3sinxcosx-sin²x=cos²x-sin²x+2√3sinxcosx=cos2x+2√3sinxcosx=cos2x+√3sin2
0≤x≤45°0≤2x≤90°60°≤2x+60°≤150°-√3/2≤cos(2x+60°)≤1/2-√3≤2cos(2x+60°)≤14-√3≤4+2cos(2x+60°)≤5y=3sin^2x-
∵cos^2x-cos^2y=(cosx-cosy)(cosx+cosy=)=-2(sin(x/2-y/2))(sin(x/2+y/2))(cos(x/2-y/2))(cos(x/2+y/2))=-s
∵-1≤cosx≤1,所以2-cosx恒≥1∴原式可化为√3sinx=2Y-cosxY===>√3sinx+cosxY=2Y三角代换:sin(x+a)=2Y/√(3+y²)∴-1≤2Y/√(