读入一批正整数(以0或负数

eak是直接跳出循环体,不再继续执行将break;改成continue;输入以0或负数结束；例如123450结果为9#include"stdio.h"inteven(intn){if(n%2==0)\

#includeintmain(){voideve(int);inta;printf("pleaseinputanumber");scanf("%d",&a);eve(a);//你的调用格式不对!你的

#include<stdio.h>inteven(intn){    if(n%2==0)     

运行通过,有问题HI：#includeintmain(){intnum,n=0,m=0;do{scanf("%d",&num);if(num>0)m++;elseif(num

#includeinteven(inta){if(a%2==0)return1;elsereturn0;}voidmain(void){intnum,odd=0;printf("请输入一批整数,以零或

int main(){\x09int n,max;\x09scanf("%d",&n);\x09max=n;\x09while(n>0)\x09{

#includeintmain(){inti,sun=0;while(scanf("%d",&i)&&i>0){sum+=i;}printf("%d\n",i);return0;}

#includevoidmain(){intnum,sum=0;scanf("%d",&num);while(num>0){if(num%2!=0){sum+=num;}scanf("%d",&num

#includeintmain(void){intnumber,sum=0;printf("Enternumber:\n");scanf("%d",&number);while(number>0){i

#includemain(){inta,b,c;b=0;c=0;while(1){scanf("%d",&a);if(!a)break;if(a%2)b++;elsec++;}printf("奇数=%

#include#includevoidmain(){char*p[10]={"zero","one","two","three","four","five","six","seven","eight

填入：sum=0;while(x>0){if(x%2==0)sum=sum+x;scanf("%d",&x);}

#includeinteven(intnum){returnnum%2;}intmain(){intsum=0,num=0;printf("Inputintegers:");while(1){scan

编程c语言输入一批正整数以0或负数为结束标志求奇数的和要求定义和调用函数已在TC2下经过测试,如果觉得好,#include<stdio.h>#

给你写个程序吧,pascal已经忘得差不多了.PROGRAMsinfile1(input,output);VARx,s1,s2:real;n1,n2:Integer;BEGINs1:=0;s2:=0;

1,n均为int型,加了括号先计算（1/n）则结果取int型.不加（）,1显示转换为float型,则计算为float型/int型,int会隐式转换为float型参加运算,结果为float型.由于加不加

、以-f(e)结尾的名词,在中学课本里,出现了不少.其名词复数形式：有的直接在.f(e)后加—s；有的要改—f(e)为ve再加-s；个别单词上述两种形式均可(如handkerchief→handker

vars:string;a:array[0..9]oflongint;i:longint;beginreadln(s);fillchar(a,sizeof(a),0);fori:=1tolength(

#includeintmain(){inta,i=0,j=0;cout再问：我还不大理解为啥会死循环唉。。能给解释一下吗？再答：因为你是while（a!=0）如果你输入一个不等于0的数while(a!

﹣a是(D)A.正数B.负数C.正数或负数D.正数或0或负数三种情况都有可能再问：为什么可能是0呢？？再答：a=0的时候，-a=0所以有可能是0记得采纳，谢谢。。