请编写fun(),他的功能是求fibonacci数列-搜答案-搜搜做题作业网

employee*delcre(employee*head,employee*head1){employee*p,*s,*q;p=head;while(head->age>55&&head->sex=

printf("f=%f\n\n",f);out=fopen("outfile.dat","w");

PrivateSubfun()ifimod2=0thenforx=itoastep2s=s*xnextxelseforx=(i+1)toastep2thens=s*xnextxendif试试看行不行吧

#includedoublefun(doubleh){returnfloor(h*100+0.5)/100;}

includeincludeddoublefun(inta,intb,intc){intp;p=(a+b+c)/2;returnsqrt(p*(p-a)*(p-b)*(p-c));}再问：ok再问：

int是整型long是长整型long的空间比int大int只能定义数-32767到32767大于这个范围用long定义按标准规定int的长度是16位或者32位,long是32位.大部分C++编译器中i

voidfun(intp,intn,inta[]){inti,t=0,j,x=0;for(i=p+1;t

#include#includeintprime(inti){intk;for(k=2;k

你说什么不对?结果不对还是什么?再问：程序通不过，你可以把代码拷贝到编译器里看下，会出现图片中的那种问题，麻烦你看下，多谢。再答：doublefun(intn,intx)改成doublefun(int

#include <stdio.h>#include <stdlib.h>int f(int n){if (n =

intfun(intx){intxx=x*x;if(xx==x//xx%10==x//xx%100==x)return1;elsereturn0;}

#include#defineN10floatfun(intnum[N[N]){inti,j,k=0,sum=0;floataverage;//下面求数组周边元素的平均值for(i=0;i再问：顶角的

上面的错了应该是intfun(){inti,sum=1;for(i=1;i

#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu

#include <stdio.h>#include <stdlib.h>#include <math.h>double f

请楼主参考采纳intfun(intt){inti;intcurrent=0;for(i=1;totalt)break;current+=i;}returncurrent;}

voidfun(intn){inti;floatresult=0.0;for(i=1;i

#includedoublefun(longlongn){n--;longlongm=n/21;longlongk=m*(m+1)/2;returnsqrt((double)k*21);}

1.intf1=0,f2=1,f3;2.returnf3;继续写：f3=f1+f2;f2=f3;f1=f2;

修改：#include#includedoublefun(intn,intx){\x05intk=1;\x05inti,j;\x05doublesum=0;\x05for(i=n;i>=1;--i)\