malab编写函数可返回矢量的最大值.最小值和平均值
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#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}
M文件中输入如下代码:functionf1=aa();disp('请输入三个数a,b,c:');a=input('a=');b=input('b=');c=input('c=');f1=min(min
楼上写的有问题,1、result=double(r);函数名写错了2、printf("%d",result);不应该是%d,而应该是%lf#include"stdio.h"doublef(double
intmax(inta,intb,intc){intd=b>c?b:c;//找到bc的最大值dreturna>d?a:d;}voidmain(){inta,b,c;printf("输入三个整数:\n"
不知道这个是否满足你的要求.#includefloat*fun(floata,floatb){floatfz[4];fz[0]=a+b;fz[1]=a-b;fz[2]=a*b;fz[3]=a/b;re
doublefun(doublex,doubley){doubler=x*x-y*y;returnr>0?r:-r;}再问:就这样就行了??不用详细点吗?再答:double r=x*x-y*
#includeintisprime(intn){\x09if(n
1.#includeintmain(){intinterPower1(intbase,intexponent);intbase,exponent,baseexponent;printf("entera
=INDIRECT("A1:A"&SUM(B1:B4))
#include <stdio.h>#include <stdlib.h>#include <math.h>double f
#include<stdio.h>unsignedlongcombinNum(intm,intn){ inti; unsignedlongx=1; if(n&
返回的y是一个数组,数组的每个点是sample.wav波形以8000Hz频率采样的离散数值.再问:再追问下,[y,fs,bits]=wavread(‘sample.wav’);中fs是指你的8k么,但
函数如下:functionind=findNearest(x,desiredVal)[m,n]=size(x);%%%%先确定x的大小erro=abs(x(:)-desiredVal);%%%%计算误
intflip(intin)//不用数组{intout=0,flag=0;if(in>-10&&inreturnin;elseif(in{flag=1;in=-in;}do{out+=in%10;ou
例如:f(x)=x+1symsxa=0;b=1;I=int('x+1',a,b)结果:I=3/2
用海伦公式比较简单.不知道你要用什么语言编写?我简单写一下C语言的:doublesabc(doublea,doubleb,doublec){doublep,s;p=(a+b+c)/2;s=squrt(
#includeintprime(inta){inti;if(a
#include#includefloatfun(inta,intb){floatc;c=sqrt(a)+sqrt(b);returnc;}intmain(){inta=12,b=20;floatc;
c还是 .c++#include<stdio.h>int jsValue(int n){\x05int a=1;\x05int 
intfoo(inta){inti,sum=1;for(i=2;i