编程求1*2*3*······*n所得的数末尾有几个零-搜答案-搜搜做题作业网

#includeintmain(){inti,n=1,sum=0;for(i=1;i

Subtest()DimiAsInteger'声明i是整数变量Fori=1To10'循环1到10Cells(i,1)=i'赋值NextEndSu

#include<stdio.h>void main(){ int sum=0,t=1,i; &nb

doublesum=0;doublem=1;for(inti=1;i

#includevoidmain(){longvalue=0,temp;inti;for(i=1;i

#includevoidmain(){inti,sum;for(i=1,sum=0;i

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

程序的实现的是这样的,先设置一个文本框,用于n值的出入.再设置一个命令按钮用于求解.代码如下：PrivateSubCommand1_Click()DimnAsInteger,iAsInteger,mA

#includeintmain(){intsum=0;intstep=1;inti;for(i=1;i

#includevoidmain(){inta,n,count=1;longintsn=0,tn=0;printf("pleaseinputaandn\n");scanf("%d%d",&a,&n);

楼上的回答当然正确,也可能用此方法.clearp=1s=0fori=1to100s=s+p*(1/i)p=-pendfor?"S=1-1/2+1/3-1/4+1/5········-1/100结果为：

#includemain(){doublesum=1;//这么做是为了减少一次循环intn;for(n=1;n

依据你的描述计算结果如图代码如下PrivateSubCommand1_Click() Sum=0 Forn=1To30 &

#include"stdio.h"main(){chara[10];inti,j;h:printf("请输入数字,注意不能超过5位:");gets(a);for(i=0;a[i];i++);if(i>

dima,i,b,casstring'声明变量a=13i=0c=1.008whileb>26b=c^(i+1)*a'b=c的i+1次方乘以ai=i+1wendmsgboxi

完整的代码,有问题再问#include <stdio.h>#include <stdlib.h>int&nb

int k=1, sum=0;&nb

#include"stdio.h"voidmain(){inti;longs=0;for(i=0;i

#includeintmain(){intn,i,sum=0,temp=1;scanf("%d",&n);for(i=n;i>0;i--){sum+=temp*i;temp++;}printf("%d

#include"stdio.h"voidmain(){intx,n,up,down,i;floatsum;printf("Inputxandn:");scanf("%d,%d",&x,&n)