编写程序,求出3-50之间所有奇数的和与所有偶数的和3-搜答案-搜搜做题作业网

#include<stdio.h>intmain(){ printf("%d",count(100)); &nb

intcount=0;for(inti=1;i

s=0a=1INPUTnDOb=nMODaIFb=0THENs=s+aENDIFa=a+1LOOPUNTILa>nPRINTsEND

PublicSubqqqqq()DimiAsIntegerDimjAsIntegerDimsAsIntegerDimCAsBooleans=0Fori=2To100C=FalseForj=2Toi-1

while(m

s=0k=0fori=1to100s=s+iifi%2=0k=k+iendifendfor?"s=1+2+3++100=",s?"1-100的偶数和：",k

#includeintmain(){inti,a,b,c;for(i=100;i

#include<math.h>voidmain(){intn1,n2,n3,n;printf("所得的数为：\n");for(n=100;n<1000;n++){n1=n%10;n

这么多数字相乘会溢出的,给你改成加法了,意思一样的declare@iintdeclare@jintset@i=0set@j=1while@j

intcount=0;for(inti=1;i

for(inti=1;i再问：{cout

cleari=0dowhilei

#includeintmain(intargc,char*argv[]){intm,n;inti;intsum;printf("Pleaseinputmandn:\n");scanf("%d%d",&

intge,shi,bai;printf("100-1000的所有水仙花数为：");for(inti=100;i

subbeisu()dimbeisu3asintegerdimbeixu7asintegerbeisu3=0beisu7=0fori=1to1000ifimod3=0thenbeisu3=beisu3

//分别计算1到1000之间所有3的倍数之和和所有7的倍数之和intmain(){intsumA=0;//3的倍数的和intsumB=0;//7的倍数的和for(inti=1;i

#include#includevoidmain(){inti,j,sum=0,s;for(i=3;i{s=sqrt((double)i);for(j=2;j{if(i%j==0)break;}if(

#includeusingnamespacestd;#defineN200intmain(){inti,j,sum=0;intlow=3,high=200;for(i=low;i

脚本语言可多了你说的是哪种呢?

楼上算法有问题,多了几个PrivateFunctionprime(nAsInteger)AsBoolean'返回值=True是素数,False不是素数DimkAsIntegerprime=TrueFo