log25-log23=log22=1
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![log25-log23=log22=1](/uploads/image/f/672094-46-4.jpg?t=log25-log23%3Dlog22%3D1)
log(14)56=[log3(56)]/[log3(14)]=[3log3(2)+log3(7)]/[log3(2)+log3(7)]=[(3/a)+b]/[(1/a)+b]=[ab+3]/[ab+
5^log25(2lg2+lg5-lg2)=5^log25(lg2+lg5)=5^log25(1)=5^0=1
这个顶多算是一种不规范的简写形式.不过在大多计算器上却都是这么写的,计算器上的log就是lg,估计这里也是仿照这种写法的吧.不推荐多用.
根据函数单调性,(lg23)^x-(lg53)^x是减函数,所以x>-y
(log5根号2*log4981)/(log251/3*log74开3次方)=(1/2log52*log79)/(1/2log51/3*1/3log74)=—3
函数y=log23(3x-2)的定义域为:{x|3x-2>0log23(3x-2)>0},解得{x|23<x≤1},故答案为:(23,1].
(log23/log24+log23/log28)(log35/log33+log35/log39)(log52/log55+log52/log525)=[(5log23)/6][(3log35)/2
log37=log27/log23所以log27=log23log37log37=log27/log23所以log27=log23log37公式logab=logcb/logca
换底公式可得log3=alog2,log7=blog3,因此log7=ablog2.对log4256也运用换底公式可得log4256=log56/log42=log(2×2×2×7)/log(2×3×
(log23+log89)(log34+log98+log32)=(log827+log89)(log916+log98+log94)=log8243•log9512=lg35lg8×lg83lg32
由log(3)7=a,log(23)=blog(3)7=log(2)7/log(2)3=a,则log(2)7=a*
Loglog=newLog();再问:上面说Logcannotberesolvedtoatype
log37^½=log33^(½b)=½b,不知这样表达有没有问题
log₂log₃log₄X=0log₃log₄X=1log₄X=3X=64log₃log₄logS
化为Log5'(2*2x)=log5'8所以2*2x=8x=2望采纳!
∵1=log33>a=log32>log31=0,b=log52<log32=a,c=log23>log22=1,∴c>a>b.故答案为:c>a>b.
lg3=alg2lg5=blg3lg20=xlg152lg2+lg5=x(lg3+lg5)2lg2+blg3=x(lg3+blg3)2lg2+ablg2=x(alg2+ablg2)2+ab=x(a+a
log23=lg3/lg2=b/a选A