java输入一个浮点数再输出该数的整数部分

楼主需要什么语言版的再问：C++再答：我只给出反序数你自己琢磨一下大致思路是这样的voidReverse(intm,intlen){if(m/10){cout

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

publicclassMax{publicstaticvoidmain(String[]args){int[]a=newint[5];System.out.println("请输入五个数：");Sca

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

#include#includevoidmain(){doublex,y;printf("请输入x和y坐标,用空格隔开\n");scanf("%lf%lf",&x,&y);doublel=sqrt(x

voidmain(){inta;scanf("%d",&a);if(a%2==0){printf("偶数");}else{printf("奇数");}}programJO;vara:integer;b

intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num

很简单,用while#includevoidmain(){intn;intm;printf("输入一个数:");scanf("%d",&n);while(n>=1){m=n%10;

#includeusingnamespacestd;intmain(void){floatf;scanf("%f",&f);printf("整数部分:%d\n",int(f));printf("小数部

可以把浮点数当初字符串来处理字符串处理函数如下：voidcut(string&str){intn=0;n=str.size()-1;stringcutter(n,'');stringstr3(n,''

#includeintmain(){floatn,n2;intn1;printf("输入一个数：\n");scanf("%f",&n);n1=int(n);n2=n-n1;printf("%d%f",

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

Reverse

方法一：你可以先将浮点数乘以100,然后取整,非四舍五入,取整后再除以100,这样不就得到了两位小数的输出了嘛方法二：你还可以强制转换为String的,然后取从开始到小数点往后两位的位置结束的字符串,

#includedoublemin(doublea,doubleb){reurn((a>b)b:a);}intmain(){doublea,b,c;printf("输入三个浮点数(用逗号","隔开):

c语言本省就有求浮点数绝对值的函数:fabs

publicclassTest{publicstaticvoidmain(String[]arsg){inttemp=1000009;StringtempStr=1000009+"";//转换成字符串

intnumber=0;Scannersc=(newScanner(System.in));try{System.out.print("请输入一个数:");number=sc.ne

楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问

importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys