用数组保存随机产生的10个介于20到50之间的整数,求其中的最大数
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#include#includevoidmain(){\x05inti,j;\x05floatsuma,sumb;\x05floatavga,avgb;\x05intmaxa,maxb;\x05int
窗体中加命令按钮,单击事件代码如下:PrivateSubCommand1_Click() Randomize Dima(1To20)AsInteger&nb
OptionBase1OptionExplicitDima(11)AsIntegerPrivateSubCommand1_Click()DimiAsIntegerPicture1.ClsPicture
PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(
Print"平均值是:"&平均改为Print"平均值是:"&平均(a)再问:为什么这么改啊?原因是什么?再答:PrivateFunction平均(a()AsInteger)AsInteger你这个函数
PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima
PrivateSubCommand1_Click()RandomizeDima(1To10)Dimmax,min,avemin=50:max=20Fori=1To10a(i)=Int(Rnd*21+3
#include#include#includeintmain(){srand((unsigned)time(0));intArray[10];inti=0;doublesum=0;intMax=-1
Dima(10)Fori=0To9a(i)=Int(100+100*Rnd)NextiFori=0To8Forj=iTo9Ifa(i)t=a(i)a(i)=a(j)a(j)=tEndIfNextjNe
PrivateSubCommand1_Click()Dima(1To10)AsIntegerRandomizeFori=1To10a(i)=Int(Rnd*100)+1Printa(i);NextPr
#includevoidmain(){inta[100],i;for(i=0;i
Dimm(99)AsInteger,n(9)AsInteger,iAsInteger,kAsIntegerRandomizeFori=0To99m(i)=Int(Rnd*100)Printm(i);k
PrivateSubCommand1_Click()RandomizeDima(1To10)Dimmax,min,avemin=50:max=20Fori=1To10a(i)=Int(Rnd*21+3
OptionExplicitPrivateSubForm_Click()'定义i循环变量,imax存放最大数,imin存放最小数,数组ishuz下标为1-10DimiAsLong,imaxAsLong
根据你的意思,我来写写,没在工具上写,没环境,你自己编译下,应该只有小错误.importjava.util.*;publicclassTest{int[]i=newint[30];//存放30个数的数
dima(9)asintegerprivatesubcommand1_click()dimiasintegerrandomizefori=0to9a(i)=int(rnd*101)text1.text
dima(30)fori=1to30a(i)=int(rnd(97+3))ifisprime(a(i))=truethenprinta(i);nextifunctionisprime(xasinteg
Subform_click()Dimi(10)Forn=1To10i(n)=Int(Rnd*30+20)Nextmaxnum=20Forn=1To10Ifi(n)>maxnumThenmaxnum=i
选择法:PrivateSubForm_Click()Dimi%,j%,a%(1To10)RandomizeFori=1To10a(i)=Int(101*Rnd)NextiFori=1To9k=iFor
#include#includeintmian(void){intarr[50]={0};srand((unsignedint)time(NULL));intnIndex=0;for(;nIndex{