用因式分解解方程4x(x-2)=5(x-2)
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2x²+x-1=0(2x-1)(x+1)=02x-1=0或x+1=0x1=1/2x2=-1
移项再化一下得(2x)²-(3x-2)²-0用平方差公式得(2x+3x-2)(2x-3x+2)=0x1=0.4,x2=2
(3x+2)^2=4(x-3)^2(3x+2)^2-4(x-3)^2=0(3x+2+2x-6)(3x+2-2x+6)=0(5x-4)(x+8)=0x=4/5或x=-8
5x平方-2x-7=0(5x-7)(x+2)=0x1=7/5x2=-2
(4-x)(3x+6)=0-3(x-4)(x+2)=0x1=4,x2=-24y(y-1)=2y(y-1)4y(y-1)-2y(y-1)=02y(y-1)=0y1=0,y2=1
(x-2)(x-2)=4x-8(x-2)(x-2)=4(x-2)(x-2)((x-2)-4)=0(x-2)(x-6)=0所以:x-2=0即x=2或x-6=0即x=6即解为:x=2,x=6(3x-4)^
1/2x²+x+1/2=0x²+2x+1=0(x+1)²=0解得:x=-1
3x²‐2x=0x(3x-2)=0则x=0或3x-2=0,x=2/3应该是这样的吧
把(x-3)作为公因数提出来(x-3)*(x-3+4x)=0(x-3)*(5x-3)=0所以x1=3,x2=3/5=0.6
9(x-1)²-(x+2)²=09(x-1)²=(x+2)²3(x-1)=x+2或3(x-1)=-x-23x-3=x+2或3x-3=-x-22x=5或4x=1x
4x^2-25x+6=0(4x-1)(x-6)=0x1=1/4,x2=6
x^2+2x-4=0(x^2+2x+1)-5=0(x+1)^2-5=0(x+1+√5)(x+1-√5)=0x1=-1-√5x2=-1+√5
(2x+1)²=2(2x+1)(2x+1)²-2(2x+1)=0(2x+1)(2x+1-2)=0(2x+1)(2x-1)=0x1=-1/2,x2=1/2再问:(2x+1)²
5x²-4x=0x﹙5x-4﹚=0x1=0x2=4/5.
移项4x²-1=0(2x+1)(2x-1)=0x=-1/2,x=1/2
(3x+2)平方=4(x一3)平方(3x+2)²-4(x一3)²=0[(3x-2)+2(x-3)][(3x-2)-2(x-3)]=0(3x-2+2x-6)(3x-2-2x+6)=0
(3x+1)(x-1)=(2x-5)(x-1)(3x+1)(x-1)-(2x-5)(x-1)=0(x-1)(3x+1-2x+5)=0(x-1)(x+6)=0x=1,x=-6
(x-1)(2x+3)+x(1-x)=0(x-1)(2x+3)-x(x-1)=0(x-1)(2x+3-x)=0(x-1)(x+3)=0x-1=0x=1x+3=0x=-3
3x²-6x=-4x+83x²-2x-8=0(3x+4)(x-2)=0x=-4/3,2再问:第三步能详细点吗谢谢--再答:十字相乘法:3x41x-2————-6x+4x=-2x