搜搜做题作业网求方程3x^2 xy y^2=3x-2y的非负整数解
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/05 15:22:58
原式=[x-y(x-y)2-y(x+y)(x+y)(x-y)]•xyy-1=（1x-y-yx-y）•xyy-1=1-yx-y•xyy-1=-xyx-y．故答案是：-xyx-y．
将xy提取公因式变成：xy（x+y）=-3*6=-18
[x(x+3)][(x+1)(x+2)]=24(x²+3x)[(x²+3x)+2]-24=0(x²+3x)²+2(x²+3x)-24=0(x²
2/(x-2)+6x/(x²-4)=3/(x+2)乘以(x²-4)得2(x+2)+6x=3(x-2)2x+4+6x=3x-68x-3x=-6-45x=-10x=-2经检验,当x=-
#include#includeintmain(){doublex=1,x2;do{x2=x;x-=(2*x*x*x-4*x*x+3*x-6)/(6*x*x-8*x+3);}while(fabs(x-
intf(floatx)返回值,错了.
3(X+1)-(X-1)=KX,令X=0,得：3+1=0,舍去,令X=1,得6=K,∴K=6.3X+3-X+1=KX(2-K)X=-4,当K-2=0,即K=2时,原方程无解,当2-K≠0,X=-4/(
原式=[(x+y)2(x-y)(x+y)+-4xy(x-y)(x+y)]×(x+3y)(x-3y)(x+3y)(x-y)=x-3yx+y，由已知得（3x-2y）（x+y）=0，因为x+y≠0，所以3x
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
x^2/C1+y^2/C2=1两边对x求导：2x/c1+2yy'/c2=0x/c1=-yy'/c2(yy')/x=-c2/c1两边对x求导：[(y'^2+yy'')x-yy']/x^2=0xyy''+
3+2x=5x5x-2x=33x=3x=1
（x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+
授你以渔a^1=aa^2=a*a5^2=253^2=93^3=3*3*3=272^4=2*2*2*2=16(a+b)^3=a^3+3ab^2+3ba^2+b^3=a^3+b^3+3ab(a+b)a+b
x/1*2+x/2*3+...+x/2007*2008=2007x(1-1/2+1/2-1/3+...+1/2007-1/2008)=2007x(1-1/2008)=2007(2007/2008)x=
2x:3=x:72x*7=3*x14x=3x14x-3x=011x=0x=0
|x-3|+|x+2|=4分3个区间讨论x>=3x-3+x+2=4x=5/2(不合要求)-2<=x<33-x+x+2=4(不是方程,等式也不成立)x<-23-x-(x+2)=4
x=1,y=0,z=9首先x、y、z都是个位数xyy可以写成100x+10y+y同理,zz可以写成10z+zyx写成10y+x等式重新代入以上化解后的式子,就是：100x+11y-11z=10y+x合
由题意知：X不等于0方程可化为4/(X^2+2X+1)+5/(X^2+2X-5)+3/2=0设X^2+2X=Y则:4/(Y+1)+5/(Y-5)+3/2=0然后通分:Y^2-2Y-15=0所以Y=5O
2x-4x=-9+3-2x=-6x=3
再答：你可以问问你们老师，，，这样的话分母为0，那么还有意义吗