c语言输入5个整数,求它们的和以及平均值
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![c语言输入5个整数,求它们的和以及平均值](/uploads/image/f/532237-13-7.jpg?t=c%E8%AF%AD%E8%A8%80%E8%BE%93%E5%85%A55%E4%B8%AA%E6%95%B4%E6%95%B0%2C%E6%B1%82%E5%AE%83%E4%BB%AC%E7%9A%84%E5%92%8C%E4%BB%A5%E5%8F%8A%E5%B9%B3%E5%9D%87%E5%80%BC)
#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p
#includevoidmain(){inta[10],i,sum=0,count=0;printf("请输入10个整数:\n");for(i=0;i再问:奇数输出不了 再答:不好意思,我是
#include <stdio.h>#define SIZE 5int main(){ int&nbs
是输入结束不会还是取整数小数不会?再问:都不会,完全没有思路,只有寻求帮助了再答:������֪��˼·����ֱ��Ҫ����再问:ֱ��Ҫ����ϣ������C++��д��˳��˵������
intmain(){intc[10];inti;for(i=0;i
给你写了,你看看吧#includeintmain(void){inta[20],i,j,sum=0,temp;for(i=0;i
#includeintmain(){inta,b;floatc;printf("请输入两个整数和一个实数\n");scanf("%d%d%f",&a,&b,&c);c=a+b+c;printf("这三
一:#includevoidmain(){inti,j;inta[5][3];for(i=0;i
#include#incluedvoidmain(){inta;intb;intc,d;a=1500,b=350;c=a/b;//商数d=a%b;//余数pritf("商数为:%d\n",c);pri
#includeintmain(){inta,b,c,d=0;scanf("%d%d",&a,&b);c=a/b;d=a%b;printf("商是:%d\n",c);printf("余数是:%d\n"
#include"stdio.h"main(){inta=0,b=0,c=0,d=0;printf("请输入两个整数:");scanf("%d,%d",&a,&b);if(b==0)printf("输
#includemain(){inta,b,c;doubleavg=0.0;scanf("%d%d%d",&a,&b,&c);avg=(a+b+c)/3;printf("%.3f",avg);再问:不
程序经过我用多组数据验证无错误,#includeintdigui(intt,intsum)//递归函数{if(t
print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente
#include"stdio.h"intmain(){intcnt;inti,j,max,n;ints[100];intbuf[100];printf("pleaseenternumber\n");s
#include“stdio.h"voidmain(){\x09inta,b,c,sum;\x09floatave;scanf("%d%d%d",&a,&b,&c);sum=a+b+c;\x09ave
#includeintmain(void){intcount=0,n,sum=0;whlie(scanf("%d",&n)!=EOF){if(n==-1)break;elsesum+=n;count+
#includeintmain(void){intn,m,max;\x05scanf("%d",n);\x05intp[n],i;\x05for(i=0,imax)//当p[0]是给max赋初值或者当
if(x%5==0){g=g+1;sum3=sum3+x;}}}//下面的大括号拿到这里printf("奇数之和为%d\n",sum1);printf("偶数之和为%d\n",sum2);printf
/*输入3个整数,输出它们的1次幂、2次幂和3次幂*/#include#definep(A)printf("%d\t%d\t%d\n",mypow(A,1),mypow(A,2),mypow(A,3)