已知函数F(X)=2SIN平方(π 4 X) 根号3COS2X-1

f(x)=cos(x/2)平方-sin(x/2)平方+sinx=cosx+sinx=√2(√2/2*cosx+√2/2*sinx)=√2(sinπ/4*cosx+sinxcos*π/4)=√2sin(

f(x)=2cos2x+sin^x-4cosx=2(2cos^x-1)+(1-cos^x)-4cosx=3cos^x-4cosx-1f(π/3)=3cos^(π/3)-4cosπ/3-1=3x(1/2

一f(x)=sin"xcos"x2sinxcosxcos2x=1sin2xcos2x=_/2sin(2x派/4)1所以T=2派/2=派"指平方“_/2”指根号2二因为X属于[0派/2]是增函数.当2x

我刚答过的题:(I)f(x)=3sin^2x+2√3sinxcosx+5cos^2x=sin^2x+2√3sinxcosx+3cos^2x+2(sin^2x+cos^2x)=sin^2x+2√3sin

函数f(x)=2sin^2(x+π/4)-√3cos2x-1=-cos(2x+π/2)-√3cos2x=sin2x-√3cos2x=2sin(2x-π/3)1.当x属于R时,函数f(x)的最小正周期T

周期是派最大值是2X=1/3派+K派（-1/6派+K派,1/3派+K派）

f(x)=cos(x/2)^2-sin(x/2)^2+sinx=cosx+sinx=√2(√2/2*cosx+√2/2*sinx)=√2(sinπ/4*cosx+sinxcos*π/4)=√2sin(

f(x)=sin(2x-pai/6)+2(cosx)^2=sin(2x-pai/6)+1+cos(2x)利用2倍角公式=sin(2x)*(√3)/2-cos(2x)*1/2+cos(2x)+1=sin

f（x）=sinx+cosx.f(x)=2f(-x),tanx=1/3（cos的平方x-sinxcosx）/（1+sin平方x）=(cos^2x-sinxcosx)/(2sinx+cosx)=(1-t

f(x)=sin²(x)+(√3)sin(x)cos(x)+2cos²(x)=3/2+√3/2sin2x+1/2cos2x=3/2+sin(2x+π/6)函数f(x)的最小正周期T

y=sinx^2+根3sinxcosx+2cosx^2=-1/2(1-2sinx^2)+1/2根3*2sinxcosx+2cosx^2-1+3/2=-1/2cos2x+二分之根3倍sin2x+cos2

因为f(x)=根号3sin(2x-π/6)+2sin的平方（x-π/12)=根号3sin(2x-π/6)-（1-2sin的平方（x-π/12)）+1=根号3sin(2x-π/6)-cos(2x-π/6

f(x)=2√3sin²x-sin(2x-π/3)=√3-√3cos2x-1/2sin2x+√3/2cos2x=√3-(1/2sin2x+√3/2cos2x)=√3-sin(2x+π/3)T

草泥马老子不答了马了那么久的字全白马了再问：。。。你好前卫啊再问：谢谢你再答：告诉你答案吧，2+√2，x=2kπ+π/2

f(x)=3sin平方x+2根号3sinxcosx-3cos平方x=根号3sin2x-3cos2x=2根号3sin(2x-π/3）

1.f(x)=2cosx*sin(x+π/3)-√3﹙sinx﹚^2+sinx*cosx=2cosx*﹙sinxcosπ/3+cosxsinπ/3﹚-√3﹙sinx﹚^2+sinx*cosx=cosx

f(x)=(sinx)平方+sinxcosx=1/2(1-cos2x)+1/2sin2x=1/2-1/2cos2x+1/2sin2x=1/2+√2/2(sin2xcosπ/4-cos2xsinπ/4)

由题意可得：f(x)=(cosx)^2-(sinx)^2-2sinxcosx=cos2x-sin2x=√2cos(2x+π/4)所以f(x)的最大值为√2,最小值为-√2

f(x)=sin²x+√3sinx*sin(x+π/2)=sin²x+√3sinxcosx=(1/2)(1-cos2x)+(√3/2)sin2x=(√3/2)sin2x-(1/2)

f(x)=2cosx+sin^2x=-cos^2x+2cosx+1令t=cosx则f(x)=-t^2+2t+1=-(t-1)^2+2因为t∈[-1,1]所以当t=1时,f(x)有最大值2