已知x=1 y分之2y-1
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![已知x=1 y分之2y-1](/uploads/image/f/4227529-49-9.jpg?t=%E5%B7%B2%E7%9F%A5x%3D1+y%E5%88%86%E4%B9%8B2y-1)
x-3y=0x=3y(2x+y)/(x^2-2xy+y^2)÷1/(x-y)=(2x+y)/(x-y)^2÷1/(x-y)=(2x+y)/(x-y)^2*(x-y)=(2x+y)/(x-y)=(2*3
x=1/3y=1/2x-(x+y)+(x+2y)-(x+3y)+...-(x+13y)=6y-13y=-7y=-7/2=-3.5
2x-y+1的绝对值+(3x+2分之3y)平方=0则2x-y+1=03x+3y/2=0,则2x-y=-1①2x+y=0②①+②,得4x=-1,则x=-1/4①-②,得-2y=-1,则y=-1/2x+y
已知/X+2/+(y-2分之1)=0那么,得到/x+2/和(y-2分之1)必须等于0.所以x=-2y=2分之一已知x=-2y=2分之一原式=-2的3次方+(-2)的2次方*2分之1+7=-8+9=1
1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3
∵(2x+y)/2=(5x+2y)/4=1∴{2x+y=2(1){5x+2y=4(2)(1)==>y=2-2x代入(2)5x+2(2-2x)=4x+4=4,∴x=0,y=2∴(x+2y+1)/(2x-
2分之3x+y=14分之5x-y=1,3x+y=2(1)5x-y=14(2)由(1)+(2)式得8x=16x=2y=-42x-3y+7=2*2-3*(-7)+7=32
∵3x-2y分之5x+y=2分之1∴(5x+y)×2=(3x-2y)×1【两边同乘以2(3x-2y),即交叉相乘】∴10x+2y=3x-2y∴10x-3x=2y+2y∴7x=4y.(1)原式x+y分之
x+y=2又20分之19x-y=5分之1等式左边加左边,右边加右边.x+y+x-y=20分之632x=20分之63x=40分之63y=40分之55
由于|x+y|≠x+y,说明x+y0则x+y=-12又4分之3+8又2分之1=-51/4+17/2=-17/4即负4又四分之一2.若y
x+y=10x-y=8/7原式=-7³/8*(x+y)³*(x-y)*4(x+y)²(x-u)²=-343/2*(x+y)^5*(x-y)³=-343
(3x-4y)÷(2x+y)=1/2所以2x+y=2(3x-4y)=6x-8y4x=9y所以x/y=9/4
因为:3分之x+1=4分之y+3=5分之x+y,所以:(x+1)/3=(y+3)/4=(x+y)/54x+4=3y+94x=3y+55x+5=3x+3y2x=3y-5x=5y=5则x+2y+3分之3x
P=(x²-y²)/(x-y)=(x+y)(x-y)/(x-y)=x+yQ=x²+2xy+y²-2xy-2y²=x²-y²所以x=
∵将x=1,y=-1带入P,Q,得P=0,Q=0,∴P=Q∴两人都不对是这样么?
因为x+y/2=3x+4y/5=1,所以x+y=2,3x+4y=5所以解方程组得x=3,带入x+5y+6/3x-y+1,得4/11
x=2y/3(4y/3+y-1)/2=(-y/3)/34y+3y-3=-2y/37y-3=-2y/321y-9=-2yy=9/23
(x+y)/2-(x-y)/3=1等式两边同时乘以6,得3(x+y)-2(x-y)=63x+3y-2x+2y=6x+5y=65y=6-xy=(6-x)/5
原式等价于10(x+1)=5(y+3)=4(x+y)10(x+1)=5(y+3)可得2x-y=15(y+3)=4(x+y)可得4x-y=15解得x=7y=13x+2y+3=363x+2y+1=48两式