:6=11,18=33 ,x=11x 6

1,（1）将（x+3/x-1）设为a（2）得a²-5a+6=0（3）因式分解（a-2）（a-3）=0（4）a1=2a2=32,化简得x³-4x²+18=0

(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1

这是两道题吗?1、两边同时乘(x-1)(x-2)(x-3）答案是x1=-1,x2=22、分母因式分解分别为(x-7)(2x+3)和(x-5)(x-7)然后同时乘(x-5)(x-7)(2x+3)答案是x

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

1、56-8X=11+X8X+X=56-119X=45X=52、3X-2=X+1+6X3X-2=7X+17X-3X=-2-14X=-3X=-3/43、7+X=2X+20-14X7+X=20-12XX+

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

6/x+1=x-5/x^2+x6/x+1=x-5/x（x+1）两边同乘x（x+1）6x=x-5x=-1但是x（x+1）≠0x≠0或-1所以该方程无解

3x*x=1+x得6x*x*x+7x*x-5x+2000=3x^2*2x+7x^2-5x+2000=(1+x)2x+7x^2-5x+2000=9x^2-3x+2000=3(3x^2-x)+2000=3

(x+7)(x+6)-(x-2)(x+1)=x^2+13x+42-x^2+x+2=14x+44=2(7x+22)

x平方-x+1=x平方-x分之6-x+1=-x分之6x-x分之6-1=0x平方-x-6=0(x-3)(x+2)=0x-3=0,x+2=0所以,x=3.x=-2

x(x-1)=18x-x=18x-x+1/4=18+1/4(x-1/2)=73/4x=1/2±√73/2

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

有种方法叫做穿针引线法,需要在纸上画出函数的简图,这个题的答案应该是-2,3,6,1

1/[x(x+3)]+1/[(x+3)(x+6)]+.+1/[(x+15)(x+18)]=1/3[1/x-1/(x+3)]+[1/(x+3)-1/(x+6)]+.+[1/(x+15)-1/(x+18)

1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=[1/x-1/(x+3)+1/(x+3)-1/(x+6)+1(x+6)-1/(x+9)]/3=[1/x-1/(x+9)]/3=3/

用换元法设x*x+11x-8＝A然后再做

左右都有X^2,故把它们都约去,剩下X分之6=X+1两边都乘以x得6=x平方+x移项x平方+x-6=0因式分解(x-3)(x+2)=0解得x=3或x=-2

17.6x-3.6x(6x-5)=4；分解等式：4x+3.6x-3.6x(6x-5)=4,进一步得：4(x-1)+3.6x(1-6x+5)=0,再合并得：4（x-1）+9.6x（1-x）=0；解得x=

首先我们可以确定一下常数项常数项的结果肯定是-1*n=-6那么n=6再看2次方项-1+m=-6那么m=-5所以m+n=1