已知:x^2 4x 4y^2 12y 8=0求xy的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 01:44:03
![已知:x^2 4x 4y^2 12y 8=0求xy的值](/uploads/image/f/4207351-31-1.jpg?t=%E5%B7%B2%E7%9F%A5%3Ax%5E2+4x+4y%5E2+12y+8%3D0%E6%B1%82xy%E7%9A%84%E5%80%BC)
如题x-24≥0,24-x≥可推出x=24,y=-8,故x/y=-3
依题意,得:x2−16≥016−x2≥0,8-2x≠0;即x2-16=0,8-2x≠0;由x2-16=0,得:x=±4;由8-2x≠0,得x≠4;综上知:x=-4;y=−98−2×(−4)=-916;
2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]
你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=(x平方-y平方)/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24
我怕来不及,等等发给你!再问:慢慢来,,,,,,再问:还没好??
多项式2x3y2-3x2y3-5x4y+6xy4-5中,x的系数依次3,2,4,1,按x的降幂排列是-5x4y+2x3y2-3x2y3+6xy4-5.
因为x+y=8,所以(x+y)^2=64,即x^2+y^2+2xy=64又因为x^2+y^2=24,所以xy=20又因为(x-y)^2=|(x+y)^2-4xy|=16所以[xy(x-y)]^2=(2
解题思路:,解题过程:最终答案:略
首先将表达式写成相乘的形式:x^2-y^2+6y=24=>x^2-y^2+6y-9=15=>x^2-(y^2-6y+9)=15=>x^2-(y-3)^2=15=>(x-y+3)(x+y-3)=15又因
X+y=10,XY=24,则X=4,Y=6或X=6,Y=4,所以(X-Y)(X-Y)=2*2=4或(-2)*(-2)=4,都为4
|x|+|y|>=0x
∵x2−4+4−x2x+2有意义,∴x2−4≥04−x2≥0x+2≠0,解得:x=2,∴y=0+1=1,∴2x+y=5.故答案为:5.
∵x2+y2+54=2x+y,∴x2-2x+1+y2-y+14=0,∴(x-1)2+(y-12)2=0,∴x=1,y=12,当x=1,y=12时,原式=1×121+12=13.故答案是13.
y<√(x-1)+√(1-x)+1/2x-1≥0,1-x≥0,即x-1≤0∴x-1=0,x=1∴y<√(x-1)+√(1-x)+1/2=1/2∴1-y>0∴|1-y|/(y-1)=(1-y)/(y-1
解∵x:y:z=1:2:3∴x=k,y=2k,z=3k∵x+y+z=24∴k+2k+3k=24即6k=24∴k=4∴x=4.y=8,z=12
已知y=根号【x-24】+根号【24-x】-8那么x-24≥0,24-x≥0故x=24所以y=0+0-8=-8所以x-y=24-(-8)=32所以X-Y的平方根是±√32=±4√2如果不懂,祝学习愉快
4x=5y,x/y=5/4(x+y)/y=x/y+1=5/4+1=9/4
证明:y=x2+6x+9x2−9÷x+3x2−3x−x+3=(x+3)2(x+3)(x−3)×x(x−3)x+3−x+3=x-x+3=3.故不论x为任何有意义的值,y值均不变.
∵-2x3m+1y2n•4xn-6y-3-m=-8x3m+n-5y2n-3-m,又∵-2x3m+1y2n与4xn-6y-3-m的积与-4x4y是同类项,∴3m+n−5=42n−3−m=1,解得:m=2
m-n又x>y所以x-m>y-n