已知3分之2x-1≥x-2分之5-3x求|x-1|-|x 3|的最大值和最小值
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![已知3分之2x-1≥x-2分之5-3x求|x-1|-|x 3|的最大值和最小值](/uploads/image/f/4206098-2-8.jpg?t=%E5%B7%B2%E7%9F%A53%E5%88%86%E4%B9%8B2x-1%E2%89%A5x-2%E5%88%86%E4%B9%8B5-3x%E6%B1%82%7Cx-1%7C-%7Cx+3%7C%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC)
5分之3x-7<2分之x-23X/5-7
A/(x-3)+1/(x+4)=[A(x+4)+(x-3)]/(x-3)(x+4)=(Ax+4A+x-3)/(x-3)(x+4)=[(A+1)x+(4A-3)]/(x-3)(x+4)∵(2x+1)/(
1/X(X+1)+1/(x+1)(x+2)+.+1/(x+99)(x+100)=1/x-1/(x+1)+1/(x+1)-1/(x+2)+.+1/(x+99)-1/(x+100)=1/x-1/(x+10
原式得:1/(x-3)=2-x/(x-3)两边同时乘以x-3得:2x-6-x=1x-6=1x=7
[(x-1)/2]-(x/3)=13(x-1)-2x=6x=9√x/(x+2)=3/11
由于A/(X+6)+B/(X-3)=(AX-3A+BX+6B)/(X+6)(X-3)=(2X+1)/(x+6)(x-3)所以,A+B=2,6B-3A=1,解得,A=11/9B=7/9
x²分之x-1=22x²=x-1(x-1)/2x²+3x²/(x-1)=2x²/2x²+3x/2x²=1+1.5=2.5
x/(x^2+x+1)=-1/2即-2x=x^2+x+1x^2+3x+1=0(x-1)/(2x^2+x^3-1)/(x^2-x+1)=(x-1)/(2x^2+x^3-1)(x^2-x+1)=(x-1)
1+2x>3+x和5x≤4x-12-x≤-1和3<x-13(x-1)<4x-2和5分之-x>2分之x+12分之1+3分之2x≤2分之-x+3分之5和3(x-1)<x-52分之1(x+3)<2和2分之x
x²-2分之x²=33x²-6=x²2x²=6x²=3(1-x分之1-1+x分之1)除以(x²-1分之x+x)=[(1-x)(1+
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你的题目是我图片里写的那样吗?
不用也可以算(x^4+x^2+1)/x^2=x^4/x^2+x^2/x^2+1/x^2=x^2+1+1/x^2你说的不对这里没有x+1/x而是x^2+2+1/x^2这个是完全平方即x^2+2*x*1/
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=
再问:再答:
(x+1)/(x+2)-1/(x+7)=(x+2)/(x+3)-1/(X+6)(X+2-1)/(X+2)-1/(X+7)=(X+3-1)/(X+3)-1/(X+6)1-1/(X+2)-1/(X+7)=
(1)(x²-9分之x+3+6+x-x²分之x)乘4x-6分之3-x=[(x+3)/(x+3)(x-3)-x/(x+2)(x-3)]×(3-x)/2(2x-3)=[(x+2-x)/
.我是分割线.是求x么?因为题中有“x(x-3)的值为0”,所以x=3或0;又因为有“除以1-x分之3x",所以x不等于0,所以x=3.对吧?..