将方式2x 3y分之x的3次方 y的3次方(x,y均为正数)中字母
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/17 20:41:00
![将方式2x 3y分之x的3次方 y的3次方(x,y均为正数)中字母](/uploads/image/f/3957118-70-8.jpg?t=%E5%B0%86%E6%96%B9%E5%BC%8F2x+3y%E5%88%86%E4%B9%8Bx%E7%9A%843%E6%AC%A1%E6%96%B9+y%E7%9A%843%E6%AC%A1%E6%96%B9%28x%2Cy%E5%9D%87%E4%B8%BA%E6%AD%A3%E6%95%B0%29%E4%B8%AD%E5%AD%97%E6%AF%8D)
∵|2x-3y+1|+(x+3y+5)的二次方=0∴2x-3y+1=0x+3y+5=0x=-2y=-1∴(-2x*y)的二次方(-y的二次方)×6xy平方的值=4x⁴y*(-y²
x+9y=y-3x4x=-8yx=-2y则x²=4y²所以原式=(4y²-y²)/(4y²+y²)=3y²/5y²=3/
利用加法交换律(1/2)*(x+y)^5+2(x+y)^2-(4/3)*(x+y)^3-(1/2)*(x+y)^5+(1/3)*(x+y)^3=(1/2)*(x+y)^5-(1/2)*(x+y)^5+
(1)原式=1/3x²-3x²-3xy+3/5y²+8/3x²+3xy+2/5y²=(1/3x²-3x²+8/3x²)+
64分之1x的6次方y的12次方=(8分之1x的3次方y的6次方)的2次方=(4分之1x的2次方y的4次方)的3次方
(2x4-4x3y-x2y2)-2(x4-2x3y-y3)+x2y2=2x4-4x3y-x2y2-2x4+4x3y+2y3+x2y2=2y3,因为化简的结果中不含x,所以原式的值与x值无关.
已知x+y=5,xy=3,代数式x3y-2x平方y平方+xy3=xy(x²-2xy+y²)=xy(x-y)²=3×[(x+y)²-4xy]=3×(25-12)=
1、(x的3次方+2x的2次方y+xy的2次方)分之(4y的2次方-x的2次方)÷(x的2次方+2xy)分之(x-2y)=x(x+y)²分之(2y+x)(2y-x)×(x-2y)分之x(x+
∵|x+y+1|≥0,|xy-3|≥0|x+y+1|+|xy-3|=0,∴x+y+1=0,即x+y=-1xy=3xy3+x3y=xy(x²+y²)=yx[(x+y)²-2
x+y=4,xy=2后者平方后二式相加再加后者平方
x3y+xy3=xy(x^2+y^2)=(√3-√2)(√3+√2)((√3-√2)^2)+(√3-√2)^2)=1*(3-2√6+2+3+2√6+2)=10
(1)原式=x2-(2y-3)2=x2-4y2+12y-9;(2)原式=4x6y2•(-2xy)-8x9y3÷(2x2)=-8x7y3-4x7y3=-12x7y3.
解(x²-1)/y÷(x+1)/y²=(x-1)(x+1)/y×y²/(x+1)=y(x-1)
∵x+y=3,∴(x+y)2=9,即x2+y2+2xy=9①,又x2+y2-3xy=4②,①-②,得5xy=5,xy=1.∴x2+y2=4+3xy=7.∴x3y+xy3=xy(x2+y2)=7.故答案
∵x-y=l,xy=2,∴x3y-2x2y2+xy3=xy(x2-2xy+y2)=xy(x-y)2=2×1=2.
a1=a2,b1=-b2,c1=c2a1=a2,b1=b2,c1不等于c2a1不等于a2,b1不等于b2,c1不等于c2
12分之1x的3次方×(-2xy)的2次方×(x-y)的3次方×(y-x)2的次方=1/12x³x4x²y²x(x-y)的5次方=1/3x的5次方y²(x-y)
2x+3y=-k+2,①3x-2y=5k+3②2*①+3*②13x=13k+13所以x=k+1代入①y=-kx-y=2k+1=5k=2