定义一个正矩阵,求其对角线之和
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#include#includeconstintMAX=100000;intgcd(inta,intb){returna%b?gcd(b,a%b):b;}booldig(charx){returnx>
#include#includevoidmain(){inta[3][3];inti,j;//i为行j为列intsum=0;intsum1=0;//输入for(i=0;i
#includevoidmain(){inti,j,a[3][3],sum=0;for(i=0;ifor(j=0;jscanf("%d",&a[i][j]);for(i=0;isum+=a[i][i]
publicclassGetSum{/***@paramargs*/publicstaticvoidmain(String[]args){//TODOAuto-generatedmethodstubi
intnSum=0;for(inti=0;i
1+5+9+7+3
晕.main(){inti,j;inta[3][3];intresult=0;for(i=0;i
intmatrix(int**aintra,intca){intsum=0;for(inti=0;i再问:��д����������� ����[][]�
对角线元素之和可以调用库函数trace,也就是矩阵的迹定义了矩阵A后,直接调用函数trace(A).
http://tieba.baidu.com/f?ct=335675392&tn=baiduPostBrowser&sc=7959986979&z=753019503&pn=0&rn=30&lm=0&
#includeintmain(){inta[5][5];for(inti=0;i<5;i++){for(intj=0;j<5;j++)scanf("%d",&a[i][j]);}ints=0;for
#include#definek3intmain(){intenter;//intk=3;intarr[k][k];inti,j,sum=0;for(i=0;i
#include#defineN6main(){inti,j,n=1,s=0,m=0,a[N][N];for(i=0;i
#include <iostream>using namespace std;void main(){/* 变量定义与初始化
#includevoidmain(){int[3][3],sum=0;inti,j;printf("enterdata:\n");for(i=0;i
用C语言实现,代码如下#include"stdio.h"#defineM3//矩阵阶数voidmain(){inta[M][M],i,j,sum=0;printf("请输入%d*%d矩阵:\n",M,
#include"stdio.h"#defineN10intmian(){inta[N][N];inti,j,sum=0;for(i=0;i
voidmain(){inta[3][3]={1,3,5,7,9,11,13,15,17},s1=0,s2=0,i,j;for(i=0;i
可参考以下程序:inta[5][5];//5*5数组inti,x,y;//x,y是两个对角线元素的和.x=0;for(i=0;i
#includevoidmain(){inta[5][5]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25},i,