定义一个圆类circle 该类有坐标半径颜色
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![定义一个圆类circle 该类有坐标半径颜色](/uploads/image/f/3871774-46-4.jpg?t=%E5%AE%9A%E4%B9%89%E4%B8%80%E4%B8%AA%E5%9C%86%E7%B1%BBcircle+%E8%AF%A5%E7%B1%BB%E6%9C%89%E5%9D%90%E6%A0%87%E5%8D%8A%E5%BE%84%E9%A2%9C%E8%89%B2)
修改如下,调试无误:#include "iostream"#include "cmath"using namespace 
#include"stdio.h"constdoubleP=3.14;classCircle{public:virtualdoubleArea();voidR(doubles);doublegetr(
可以在父类中写虚函数的定义如果子类中重写了该虚函数,则根据指针可以调用到子类的虚函数;否则的话,调用的是父类的虚函数.极端情况下,纯虚函数也可以拥有定义,但由于不能生成父类的实例,定义出的函数不能直接
#include <iostream>using namespace std;class Box {\x09float leng
classcircle{intx;inty;floatradius;public:voidsetpoint(int&x,;int&y);voidsetradius(float&radius);floa
namespaceEX1_4{publicclassshape{publicdoublePI=3.14;}publicclassRectangle:shape{publicintx,y,s,l;pub
classcircle{public:circle(doubleradius):_radius(radius){}~circle(void);private:double_radius;public:
教材上一般都有,这是标准例题.
#include#includeusingstd::cout;usingstd::cin;usingstd::endl;usingstd::string;classBook{public:Book(s
把这三个类分别放到三个.java文件中,然后编译运行即可.publicclassCircle{privatedoubler;publicCircle(doubler){this.r=r;}public
2种差不多的方法,自己在VC6.0上面试试#include<iostream>usingnamespacestd;#definepi3.14classcircle{public:circl
#includeusingnamespacestd;classCircle{public:Circle(doubler=0):radius(r){}doubleArea(){return3.14*ra
#include"iostream"#include"cmath"usingnamespacestd;classCircle{public: Circle(doublex=0,doubley
publicclassCircle{privatedoubleradius;publicCircle(doubler){this.radius=r;}publicstaticvoidmain(Stri
classa{publcstatevoidb(){}}
classCircle{privatedoubleradius;publicCircle(){this.radius=0;}publicCircle(doubler){this.radius=r;}p
abstractclassShape{publicShape(){}publicfloatGetPerim(){return0;}}classRectangleextendsShape{private
不要提出这种问题,代码还是自己动手写的好,写的过程中遇到麻烦,再拿出来问的话,我想会有更多人乐意帮你解答的再问:来不及哦!!今天晚上要交!!没时间慢慢写!!我对c++也不是很熟!急求高手流利的给个程序
publicclassWb{doublei=5.0;doublefindArea(){returnradius*radiu*3.14159;}publicstaticvoidmain(string[]