定义一个圆类,输出半径.面积

classCircle{private:intm_nR;public:Circle(intnR){m_nR=nR;}floatOutputF(){return2*3.1415926*(float)m_

importjava.util.Scanner;classRound{\x09publicdoubleperimeter(doubleradius){\x09\x09returnradius*2;\x

classCircle{\x09privatedoubler;\x09publicvoidsetR(doubler)\x09{\x09\x09this.r=r;\x09}\x09publicdoubl

#include#includeusingnamespacestd;classCircle{doubler,Area,Circumference;public:Circle(doublea=0);Ci

function[SV]=sphere(R)%定义函数S=pi*R^2;%求圆的面积V=4/3*pi*R^3;%求求的体积调用方法[ab]=sphere(1)

拿去慢慢研究吧#includeintmain(void){doubler=3.0,pi=3.14159,s;s=r*r*pi;printf("圆的面积为%lf",s);return0;}

classCircle{public:Circle(intnr){r=nr;}Circle(){}public:intr;intArea(){return3.14*r*r;}};classB{publ

#includeusingnamespacestd;classcircle{private:doubleradius;public:circle(doubler=0.0);voidinput();do

PrivateSubCommand1_Click()DimrAsSingleDimcAsSingleDimsAsSingler=Val(Text1.Text)c=2*3.14159*rs=3.1415

packagehfuu.cdj;publicclassCircle{privatedoubler;Circle(doubleR){if(R>=0){r=R;}else{Syst

1）这个直接BigDecimal类搞定,按圆面积公式算2）同上,带上两个输入参数,按三角形面积公式算3）按照奇数的概念,输出不能被2整除的数呗再问：能把具体的代码给出吗？就快要考试了，急着用，不汇编代

（法1）#includeusingnamespacestd;#definePI3.1415926classCircle{doubler;public:Circle(doubleR=0){r=R;}vo

#includemain(){inta,b;charc;scanf("%d,%d,%c",&a,&b,&c);printf("\na=%d,b=%d,c=%c\n",a,b,c);}输入a,b,c之间

#include"stdafx.h"#include#includeusingnamespacestd;classCircle{doubler,Area,Circumference;public:Ci

#includeusingnamespacestd;classCircle{public:Circle(doubler=0):radius(r){}doubleArea(){return3.14*ra

classcircle{doublerd;//半径成员public:circle(){rd=0.0;}//构造函数cirle(doubleb){rd=b;}//重构构造函数doublezc(){ret

第一段程序：m=pie*r*r,这句逻辑上有问题,m为输入值,r未赋值,默认0,for(i=1;i

这个是pascal的做法programabcconstpai=3.14varR,Area:real;beginwriteln("pleaseinputanumberforr:");readln(r);

#includeusingnamespacestd;#definepi3.14classcircle{public:circle(doubler=0.0){}circle(circle&c){}dou

publicclassWb{doublei=5.0;doublefindArea(){returnradius*radiu*3.14159;}publicstaticvoidmain(string[]