6x[m-n]-8[n-m]平方
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![6x[m-n]-8[n-m]平方](/uploads/image/f/375362-26-2.jpg?t=6x%5Bm-n%5D-8%5Bn-m%5D%E5%B9%B3%E6%96%B9)
因为x^m=3,x^n=6所以x^(m-n)=x^m/x^n=3/6=1/2x^(3m-2n)=x^3m/x^2n=(x^m)^3/(x^n)^2=(3^3)/(6^2)=3/4
2x(M+3x)=6x²y²+N2xM+6x²=6x²y²+N所以N=6x²,且2xM=6x²y²,即M=3xy&sup
解析2*(M+3x)=2*m+6x=6x²y²+N两边比较2*m=6x²y²m=3x²y²N=6x再问:我没看明白。请问这几个算式都是为什么
3x(M-5x)=6x^2y^3+N,3x*M-15x^2=6x^2y^3+NM=2xy^3N=-15x^2
由于2x(M+3x)=6x^2y^2+N,所以2xM+6x^2=6x^2y^2+N比较可知2xM=6x^2y^2,6x^2=N所以M=3xy^2,N=6x^2
yn²-?再问:就是y的n2次方,看问题补充再答:方程(m-2)x|m|-1+(n+3)yn²-8=6是二元一次方程则m-2≠0|m|-1=1(n+3)≠0n²-8=1得
(m+n)2-6(m+n)+9=(m+n-3)2
(2x^3m*x^2n)/(x^m*x^n)^2*x^n=(2*6^3*9^2)/(6*9)^2*9=4/3
(2m-6)x^(|n|+1)+(n+2)y^(m^2-8)=0要使得(2m-6)x^(|n|+1)+(n+2)y^(m^2-8)=0对所有x,y都成立,所以必须有2m-6=0且n+2=0所以m=3,
〈(m-n)²(m-n)+(m+n)²(m+n)〉〈(m-n)²(m-n)-(m+n)²(m+n)〉=〈m(2m²+2n²)+n(4mn)〉
6a(m-n)²-8(n-m)³=6a(m-n)²+8(m-n)³=2(m-n)²(3a+4m-4n)
x^(2m+2n)*x^(3m-2n)=8*4x^(2m+2n+3m-2n)=32x^5m=2^5(x^m)^5=2^5x^m=2x^(2m+2n)=8x^2m*x^2n=8(x^m)^2*x^2n=
原式=(m-n)²+2(m-n)-6=(m+n-2)(m+n+3)
软件算的m->1/16(64+d2^2-d3^2+(256d1d2)/(-256+4d1^2-8d1d2+8d2^2-8d2d3+4d3^2)-(4d1^3d2)/(-256+4d1^2-8d1d2+
当m-n=5(m+n)时,[6(m-n)]/(m+n)-[5(m+n)]/(m-n)]=[30(m+n)]/(m+n)-[5(m+n)]/[5(m+n)]=30-1=29
原式=x²+n²-6n+4m+13=x²+(n²-6n+9)+4m+4=x²+(n-3)²+4(m+1)即:x²+(n-3)
4(m-n)-3m+3n+8=4(m-n)-3(m-n)+8=(m-n)+8∵m-n=6∴原式=6+8=14
6(m-n)³
x²-6x+m=(x-2)(x-n)x²-6x+m=x²-(2+n)x+2n∴2+n=6m=2n∴n=4;m=8
2x+n/m=m/n-(m/n+n/m)x(m/n+n/m+2)x=m/n-n/m﹙m+n﹚²x/﹙mn﹚=﹙m+n)(m-n)/﹙mn﹚∵m+n不等于0∴x=(m-n)/﹙m+n﹚