4xy²-4x²y-y三次方
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![4xy²-4x²y-y三次方](/uploads/image/f/327048-24-8.jpg?t=4xy%C2%B2-4x%C2%B2y-y%E4%B8%89%E6%AC%A1%E6%96%B9)
原式=2xy(x²+2xy+y²)=2xy(x+y)²=2*2*4²=64
x^2=y+4,所以x^2-y=4y^2=x+4,所以y^2-x=4x^3-2xy+y^3=(x^3-xy)+(y^3-xy)=x(x^2-y)+y(y^-x)=4x+4yx^2=y+4,y^2=x+
4x的三次方y+4x的平方y的平方+xy的三次方=xy(4x^2+4xy+y^2)=xy(2x+y)^2肯定对望采纳
-x²y²+4xy³-4y⁴=-y²(x²-4xy+4y²)=-y²(x-2y)²
原式=2xy(4x²-2x-1)再问:求过程再答:没有提取公因式
4xy平方一4x平方y一y三次方因式分欿提取公因式y得y(4xy-4x^2-y^2)=-y(-4xy+4x^2+y^2)=-y(2x-y)^2您好,很高兴为您解答,hua395288466您答疑解惑如
原式=(x^4+xy³)-(2y^4+2x³y)=x(x³+y³)-2y(x³+y³)=(x-2y)(x³+y³)=(x
(2x^4)y³-x³y^4=(x³y³)(2x-y)=(xy)³(2x-y)=4³×(1/16)=4
-4x的平方+16x=-4x(x-4)-4x的三次方y+16x的二次方=-4x²(xy-4)y的二次方-16xy的三次方=y²(1-16xy)提示:因式分解,运用提公因式法
再问:谢谢大神再答:有问题继续密我
x²y³-2x(4xy³)=x²y³-2x²y³=-x²y³
原式=(﹣4x²y)·(﹣x²y²)·2xy³=(﹣4)×(﹣1)×2×(x²y·x²y²·xy³)=8x的5次方·y的
=xy(4x²+4xy+y²)=xy(2x+y)²
4x的三次方y+4x²y²+xy的三次方=xy(4x²+4xy+y²)=xy(2x+y)²
x³y-xy³=xy(x²-y²)=xy(x+y)(x-y)
xy(x+y)²-4x³y³=xy[(x+y)²-4x²y²]=xy(x+y+2xy)(x+y-2xy)
∵X+Y=3,∴(X+Y)^2=9,即X^2+2XY+Y^2=9,∵x^2+y^2-3xy=4∴XY=1(以上两式相减)∴X^2+Y^2=7∵x^3y+xy^3=XY(X^2+Y^2)=1*7=7(因
(x+y)(x-y)-(4x³y-8xy³)÷2xy=x²-y²-(2xy)(2x²-4y²)÷2xy=x²-y²-(2
x三次方-3x²y+3xy²+4x²y-xy²+y的三次方=x三次方+2xy²+x²y+y的三次方当x=-1,y=-3时原式=-1-18-3
∵x²+y²+6x-2y+10=0∴(x²+6x+9)+(y²-2y+1)=0即(x+3)²+(y-1)²=0由平方的非负性可得(x+3)&