3.编程实现,随意输入五个数,输出其中最大的一个.(选作)

#includeintmain(){inta,b;scanf("%d%d",a,b);if(a>b)printf("%d",a);elseprintf("%d",b);return0;}

clearinput"请输入第1个数："toainput"请输入第2个数："tobc=min(a,b)dowhilec>0ifa%c=0andb%c=0s=cexitendifc=c-1enddo?"

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

#includevoidmain(){charx[100];inti;printf("请输入英语句子\n");gets(x);x[0]=x[0]-32;for(i=1;x[i]!='\0';i++){

intfun(intn){returnn%2;}intmain(){intn;printf("\n输入要判断的整数");scanf("%d",&n);if(fun(n)==0)printf("\n%d

算法一：#includemain(){intn1,n2,gcd=1,k=2;scanf("%d%d",&n1,&n2);while(k0;i--)if(n1%i==0&&n2%i==0)printf(

#includeusingnamespacestd;voidjudge(intx,inty){if(x%y)return0;cout

//输入范例假设n赋值为4/*1234(回车)2345(回车)3456(回车)5678(回车)注意输入时数字间要有空格间隔*/#includevoidmain(){inti,j;intsum=0;//

PrivateSubCommand1_Click()DimaAsLongDimiAsLongDimsAsBooleans=Truea=InputBox("请输入一个自然数","输入")'-------

百度一下BCWHY去哪里提问吧.知道这里没人回答了.

#includeintmain(){intn,i,j;doublesum=0.0;printf("请输入项数n:\n");scanf("%d",&n);if(n1000)printf("输入数字超出范

#includevoidmain(){intn[5];intt[5];for(inti=0;i{printf("请输入第%d个数字:",i);scanf("%d",n[i]);//如果要求每次输入的数

Subtest()DimNumAsLong,Arr(1To5)Forn=1ToUBound(Arr)Num=Application.InputBox("请输入第:"&n&"个数字:","数字输入窗口"

#includevoidexchange(int*a,int*b){intt=*a;*a=*b;*b=t;}intmain(){intx,y,z,t;scanf("%d%d%d",&x,&y

不会那个函数就自己编了,下面是我编的,输入多少个数都能从大到小排functiony=paixu(a)n=length(a);fori=1:n-1forj=i+1:nifa(i)再问：functiony

PrivateSubForm_Load()DimaAsInteger,bAsInteger,cAsInteger,MaxAsInteger,MinAsIntegera=InputBox("请输入a值"

#include<stdio.h>intmain(){charop;doubledata1,data2,r;printf("请输入算术式如3*15\n");scanf("%lf%c%lf"

用递归吧,省时省力,代码如下:OptionExplicitPrivateSubCommand1_Click()MsgBoxcal(103601)EndSubFunctioncal(ByValnAsLo

#include"stdlib.h"#include"stdio.h"voidmain(){inta,b;scanf("%d%d",&a,&b);a=a*a;b=b*b;inttemp=a+b;if(

importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.