化简[(x方-4x 4分之x方-4) (x 2分之2-x)] x-2分之x-搜答案-搜搜做题作业网

y=|4-x²|/(4-x²)-xx>2或x

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f(X)=1-X方分之1+X方

f(1/x)=1-x^2+1/x^2=-f(x)直接代入即可再问：能写的再具体点吗我不太明白谢谢再答：哦我把题目看错了你的题目是对的吗再问：嗯题目是对的加我Q1047763981这样说方便再答：我没有

点图把图放大看再问：（1）已知1/a-1/b=2,求2a-ab-2b/b-3ab-a的值（2）2x+6/4x-4x+x^2÷（x+3)再答：（1/a）-（1/b）=2（1/a）×ab-（1/b）×ab

x²+5x-1=0除以x得x+5-1/x=0x-1/x=5x²+1/x²=(x-1/x)²+2=5²+2=27x^4+1/x^4=(x²+1

2-x分之x-x方+4x+4分之4-x方=2-x/x-x²+4x+4/4-x²=2-1-x²+4x+1-x²=2+4x-2x²

x四次方-6x三次方+9x二次方分之x二次方-3x=x(x-3)/x²（x²-6x+9）=(x-3)/x(x-3)²=1/x(x-3)=1/(x²-3x)如追加

x^2/(x^4+x^2+1)取倒数(x^4+x^2+1)/x^2=x^2+1+1/x^2=x^2+2+1/x^2-1=(x+1/x)^2-1=3^2-1=8(取倒数)所以x^2/(x^4+x^2+1

像这种题目也可以用特殊值去做,比如令x=1,代入方程求出y,再代入所求的式子就可以得出答案.

这道题,谁要是能理解是什么式子,就已经是大神了

1/(a-x)-1/(a+x)-2x/(a^2+x^2)-4x^3/(a^4+x^4)=[(a+x)-(a-x)]/[(a-x)(a+x)]-2x/(a^2+x^2)-4x^3/(a^4+x^4)=2

（x^2+2x+1）/(x^2-3x-4)=(x+1)^2/(x+1)(x-4)=(x+1)/(x-4)

原式=(x+1)//(x²+1)*(x²+1)(x+1)(x-1)/(x+1)³-(x-3)/(x+1)=(x-1)/(x+1)-(x-3)/(x+1)=(x-1-x+3

把每个式子因式分解x的方+5x+4=（x+1）(x+4)x方-5x+6=(x-2)(x-3)………………

x^2-3x+1=0x^2+1=3xx+1/x=3(x+1/x)^2=9x^2+1/x^2+2=9x^2+1/x^2=7(x^2+1/x^2)^2=49x^4+1/x^4+2=49x^4+1/x^4=

=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+

x方-1分之x方+x化简2x(1+x)

(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x

(x-y)²/(xy)-(x²-y²)/(xy)=（2y²-2xy)/(xy)=(2y-2x)/x

原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]×x/(x-4)=[(x²-4-x²+x)/x(x-2)²]×x/(x-4)=[(x-4)/x(x-