化简y分之x²的平方*x分之y²的立方除以-x分之y的四次方-搜答案-搜搜做题作业网

原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)

（x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=（x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)

(-y分之x的平方)的平方乘以(-x分之y的平方)的立方除以(-x分之y)的4次方=x^4/y²×（-y^6/x³）×x^4/y^4=-x^8y^6/(x³y^6)=-x

（x分之x-y）-（y分之x+y）+（2xy分之x的平方-y的平方）=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^

樱桃_小纯子：(x²-2xy+y²-1)/(x-y-1)=[(x-y)²-1]/(x-y-1)=[(x-y+1)(x-y-1)]/(x-y-1)=x-y+1

已知5x-4y=0,切xy≠0,x/y=4/5;求(x平方-y平方)分之(x平方+y平方)-(x-y)分之(x+y)的值=(x²+y²)/(x²-y²)-(x+

1)显然,x,y均为负数.x*√(-y/x^2)+y*√(-x/y^2)=x/(-x)*√(-y)+y/(-y)*√(-x)=-√(-x)-√(-y)2)a=1/(2+√3)=(2-√3)/[(2+√

2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2

原式=xy/(x-y)(x+y)÷(2y)/(x-y)(x+y)=x/2再问：再问：

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

（x/2y）²×（y/2x）-x/y²÷（2y²/x）=x²/2y×（y/2x）-（x/y²）×（x/2y²）=x/8y-x²/（

[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x

原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+

(x-y)²/(xy)-(x²-y²)/(xy)=（2y²-2xy)/(xy)=(2y-2x)/x

2y-xy分之x的平方-2x=x（x-2）/y(2-x)=-x/y;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,

现将括号里的通分x2-y2可约去最后的y分之2再问：能具体一点吗再答：原式=((x+y+x-y)/(x2-y2)÷（x的平方-y的平方分之xy）=2x/(x2-y2)×(x2-y2)/xy=y分之2只

（1-y+x分之y）÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x

x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)

x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²