分解因式6X平方-7XY加2Y的平方
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![分解因式6X平方-7XY加2Y的平方](/uploads/image/f/2338616-56-6.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F6X%E5%B9%B3%E6%96%B9-7XY%E5%8A%A02Y%E7%9A%84%E5%B9%B3%E6%96%B9)
原式=(x-y)²-2(x-y)+1=(x-y-1)²
xy^2-2xy+2y-4=xy(y-2)+2(y-2)=(xy+2)(y-2)
x³-2x²y+xy²=x(x²-2xy+y²)=x(x-y)²
1)—(x+y)四次方2)(3x+y)(3x-y+2)3)(x-3)(7x+y)4)(1+x-2y)(1-x+2y)5)5(y-x)平方(1-2y+x)6)6(a-b)平方(a-2b)7)(x+y-2
3x³-6x²y+3xy²=3x(x²-2xy+y²)=3x(x-y)²
8(x^2-2y^2)-x(7x+y)+xy=8x^3-16y^2-7x^2-xy+xy=8x^3-16y^2-7x^2无法再分解
求根法:x^2+xy-2y^2+2x+7y-3=x^2+x(y+2)-2y^2+7y-3,△(x)=(y+2)^2-4(-2y^2+7y-3)=9y^2-24y+16=(3y-4)^2,x1=[-(y
2.6x²-13xy+6y²+22x-23y+20=(2x-3y)(3x-2y)+22x-23y+4×5=(2x-3y+4)(3x-2y+5)3.(x²+4x+8)
双十字相乘.
=(3x)²-2*3x*2y+(2y)²=(3x-2y)²
1x²+2xy-3y²=x²+2xy+y²-4y²=(x+y)²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-
=7x²-4x²+4xy-y²=7x²-(2x-y)²=(√7x+2x-y)(√7x-2x+y)本题答案不唯一的
1)2x²+3x-6有两种方法(1)求根法对于关于x的方程ax²+bx+c=0,若x1,x2是其两根那么ax²+bx+c=a(x-x1)(x-x2)设2x²+3
x3次方减4xy平方减2x平方y加8y三次方=x^2(x-2y)-(2y)^2(x-2y)=(x-2y)(x^2-(2y)^2)=(x+2y)(x-2y)^2
2x的平方-xy-6y的平方=(2x-3y)(x+2y)
2x^2+3xy-2y^2-x+8y-6=(x+2y)(2x-y)-x+8y-6=(x+2y-2)(2x-y+3)
(1)3x²-4xy+6y²Δ=4²-4×3×6=16-72
(xy-1)^2+(x+y-2xy)(x+y-2)=(xy-1)^2+4xy+(x+y)^2-2(xy+1)(x+y)=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=(x+1)^2(y+